Django的ascii码编解码器不能编码字符

In Django I want to use a simple template tag to truncate data.

在Django中，我想使用一个简单的模板标记来截断数据。

This is what I have so far:

这是我目前所拥有的:

@register.filter(name='truncate_simple')
def truncate_char_to_space(value, arg):
    """
    Truncates a string after a given length.
    """
    data = str(value)
    if len(value) < arg:
        return data

    if data.find(' ', arg, arg+5) == -1:
        return data[:arg] + '...'
    else:
        return data[:arg] + data[arg:data.find(' ', arg)] + '...'

But when I use it I get the following error:

但是当我使用它时，我得到了如下的错误:

{{ item.content|truncate_simple:5  }}

Error:

错误:

'ascii' codec can't encode character u'\u2013' in position 84: ordinal not in range(128)

'ascii' codec不能编码字符u'\u2013'在位置84:序数不在范围(128)

Error is on line starting data = str(value)

在开始数据= str(值)时出错

Why?

为什么?

3 个解决方案

#1

try to use unicode() to convert value (instead of str()):

尝试使用unicode()来转换值(而不是str()):

data = unicode(value)

#2

If you're using django and python 2.7 this fixes it for me:

如果你使用的是django和python 2.7，那么这就为我修复了:

from django.utils.encoding import python_2_unicode_compatible

@python_2_unicode_compatible
class Utente(models.Model):

see https://docs.djangoproject.com/en/dev/ref/utils/#django.utils.encoding.python_2_unicode_compatible

看到https://docs.djangoproject.com/en/dev/ref/utils/ django.utils.encoding.python_2_unicode_compatible

#3

@max4ever 's answer works for me. also sometimes you should put this line in the head of python files:

@max4ever的回答对我很管用。有时你也应该在python文件的开头写上这句话:

from __future__ import unicode_literals

it can be helpful when solving unicode encoding issues like this one.

它可以帮助解决像这样的unicode编码问题。

#1