Swift将整数转换为2个字符的十六进制字符串

I am trying to get a two character hex value from an integer:

我想从一个整数中获取一个两个字符的十六进制值:

let hex = String(format:"%2X", 0)
print ("hex = \(hex)")

hex = "0"

十六进制=“0”

How can I format String to result in always 2 characters, in this case I would want

如何格式化String以产生总共2个字符,在这种情况下我想要

hex = "00"

十六进制=“00”

1 个解决方案

#1

You can add a padding 0 before the formatter string:

您可以在格式化程序字符串之前添加填充0:

let hex = String(format:"%02X", 0)

Result:

let hex = String(format:"%02X", 0) // 00
let hex = String(format:"%02X", 15) // 0F
let hex = String(format:"%02X", 16) // 10