sqlserver 生成UUID随机码

CREATE FUNCTION [dbo].[FunGetUUID32](@newid varchar(36))
RETURNS VARCHAR(32)
AS
BEGIN
    DECLARE @id VARCHAR(32);  

    select @id=SUBSTRING(@newid,1,8)+SUBSTRING(@newid,10,4)+SUBSTRING(@newid,15,4)+ SUBSTRING(@newid,20,4)+SUBSTRING(@newid,25,12)  

    RETURN @id
END 

--使用如下
select dbo.[FunGetUUID32](NEWID());