剑指Offer25 二叉搜索树转换为排序双向链表

时间:2022-02-05 05:50:41
 /*************************************************************************
> File Name: 25_BSTConvert.cpp
> Author: Juntaran
> Mail: JuntaranMail@gmail.com
> Created Time: 2016年08月31日 星期三 15时06分28秒
************************************************************************/ #include <stdio.h>
#include <malloc.h> // 二叉树结构体
struct TreeNode
{
int val;
TreeNode* left;
TreeNode* right;
}; // 构造二叉搜索树
TreeNode* InsertNode(TreeNode* tree, int val)
{
if (tree == NULL)
{
tree = new TreeNode();
tree->left = NULL;
tree->right = NULL;
tree->val = val;
}
else if (tree->val > val)
tree->left = InsertNode(tree->left, val);
else if (tree->val < val)
tree->right = InsertNode(tree->right, val);
return tree;
} void PrintTree(TreeNode* tree)
{
if (tree == NULL)
return;
PrintTree(tree->left);
printf("%d ", tree->val);
PrintTree(tree->right);
} void PrintList(TreeNode* list)
{
printf("\n");
if (list == NULL)
return;
TreeNode* node = list;
while (node)
{
printf("%d ", node->val);
node = node->right;
}
printf("\n");
} /************************************************************************/
// 剑指Offer写法
void ConvertNode(TreeNode* node, TreeNode** last)
{
if (node == NULL)
return; TreeNode* current = node; // 对tree的左子树进行转换,last是转换后链表最后一个结点的指针
if (current->left != NULL)
ConvertNode(current->left, last);
// 调整tree的left指针,指向上一个结点
current->left = *last;
// 调整指向最后一个结点,right指向下一个结点
if (*last != NULL)
(*last)->right = current; // 调整指向最后链表一个结点的指针
*last = current; // 对tree的右子树进行转换,last是转换后链表最后一个结点的指针
if (current->right != NULL)
ConvertNode(current->right, last);
} // 二叉搜索树转换为排序双向链表
TreeNode* Convert(TreeNode* root)
{
if (root == NULL)
return NULL; TreeNode* last = NULL;
ConvertNode(root, &last); TreeNode* head = root;
// 找到最左边的结点,即转换后链表的头结点
while (head && head->left)
head = head->left;
return head;
}
/************************************************************************/ /************************************************************************/
// 一个递归写法 TreeNode* leftLast = NULL;
TreeNode* Convert2(TreeNode* root)
{
if (root == NULL)
return root;
if (root->left==NULL && root->right==NULL)
{
leftLast = root;
return root;
} // 左子树改造为双链表
TreeNode* left = Convert2(root->left);
// 左子树链表不为空,root追加到左子树链表
if (left != NULL)
{
leftLast->right = root;
root->left = leftLast; // 构造双向链表
}
leftLast = root;
// 右子树改造为双链表
TreeNode* right = Convert2(root->right);
// 右子树链表不为空,链表追加到root后
if (right != NULL)
{
right->left = root;
root->right = right;
}
return left != NULL ? left : root;
}
/************************************************************************/ int main()
{
TreeNode* tree = NULL;
for (int i = ; i > ; --i)
{
tree = InsertNode(tree, i);
}
for (int i = ; i <= ; ++i)
{
tree = InsertNode(tree, i);
}
PrintTree(tree);
// tree = Convert(tree);
tree = Convert2(tree);
PrintList(tree); return ;
}