Python Tkinter 简单登录界面的实现

如下所示：

from tkinter import *

class reg (frame):
  def __init__(self,master):
    frame = frame(master)
    frame.pack()
    self.lab1 = label(frame,text = "账户:")
    self.lab1.grid(row = 0,column = 0,sticky = w)
    self.ent1 = entry(frame)
    self.ent1.grid(row = 0,column = 1,sticky = w)
    self.lab2 = label(frame,text = "密码:")
    self.lab2.grid(row = 1,column = 0)
    self.ent2 = entry(frame,show = "*")
    self.ent2.grid(row = 1,column = 1,sticky = w)
    self.button = button(frame,text = "登录",command = self.submit)
    self.button.grid(row = 2,column = 1,sticky = e)
    self.lab3 = label(frame,text = "")
    self.lab3.grid(row = 3,column = 0,sticky = w)
    self.button2 = button(frame,text = "退出",command = frame.quit)
    self.button2.grid(row = 3,column = 3,sticky = e)
  def submit(self):
    s1 = self.ent1.get()
    s2 = self.ent2.get()
    if s1 == 'admin' and s2 == '123':
      self.lab3["text"] = "登陆成功"
    else:
      self.lab3["text"] = "用户名或密码错误!"
    self.ent1.delete(0,len(s1))
    self.ent2.delete(0,len(s2))
root = tk()
root.title("用户登录")
app = reg(root)
root.mainloop()

以上这篇python tkinter 简单登录界面的实现就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持服务器之家。

原文链接：https://blog.csdn.net/qq_32005671/article/details/73410591