第二个ajax请求不起作用

I made an ajax website calling pages from /pages folder inside an ajax-container div in my index.php.

我创建了一个ajax网站,在我的index.php中的ajax-container div中调用/ pages文件夹中的页面。

Now i want to make a second ajax request after the first ajax request success but the second request will be only on certains page,

现在我想在第一个ajax请求成功后发出第二个ajax请求,但第二个请求只会在某些页面上,

for example: i call the page work.php and inside this page i want to call a page work-slider from the same folder and replace the work.php page by work-slider.php in my ajax-container div when i click on images link-in but i can't find a solution for make it,

例如:我调用页面work.php,在这个页面里面我想从同一个文件夹中调用一个页面工作滑块,当我点击时,在我的ajax-container div中用work-slider.php替换work.php页面图像链接但我找不到制作它的解决方案,

This is my actual code:

这是我的实际代码:

index.php:

<div id="ajax-container">
 <?php
  $d = "pages/";
  if (isset($_GET['p'])) {
     $p = strtolower($_GET['p']);
     if (preg_match("/^[a-z0-9\-]+$/", $p) && file_exists($d . $p . ".php")) {
         include $d . $p . ".php";
     } else {
         include $d . "404.php";
     }
  } else {
     include $d . "home.php";
  }
 ?>
</div>

Ajax function:

var afficher = function(data) {

    $('#ajax-container').fadeOut(250, function() {
        $('#ajax-container').empty();
        $('#ajax-container').append(data);
        $('#ajax-container').fadeIn(100, function() {});

    });
};

var lastRequest = null;
if (lastRequest !== null) {
    lastRequest.abort();
}

var loadPage = function(page, storeHistory) {
    if (typeof storeHistory === 'undefined') {
        storeHistory = true;
    }


    lastRequest = $.ajax({
        url: "pages/" + page,
        cache: false,
        success: f$.ajax({
    url: "pages/" + page,
    cache: false,
    success: function(resultFirst) {
        afficher(resultFirst);
        if (storeHistory === true) {
            history.pushState({
                'key': 'value',
                'url': page
            }, '', page);
        }
        $.ajax({
          
          // How can i define pageIn variable ?? 
          
          url: "pages/" + pageIn,
          cache: false,
          success: function(resultSecond) {
             afficher(resultSecond);
          }
      });
    },
    error: function(XMLHttpRequest, textStatus, errorThrown) {
        afficher('erreur lors du chagement de la page');
    }
});

    return false;
};

window.addEventListener('load', function() {
    setTimeout(function() {
        window.addEventListener('popstate', function(e) {
            if (e.state === null) {
                loadPage('home.php');
            } else {
                loadPage(e['state']['url'], false);
            }
        });
    }, 0);
});

  
  // link inside index.php

$('.link').bind('click', function(e) {
    e.preventDefault();
    var page = $(this).attr('href');
    loadPage(page);
    return false;
});

  // second link inside called page
  
  $('.link-in').bind('click', function(e) {
    e.preventDefault();
    var pageIn = $(this).attr('href');
    loadPage(pageIn);
    return false;
});

1 个解决方案

#1

If that .link-in tag if dinamically inserted into the DOM after the page loads, the bind() method will fail: bind() attach listeners to elements it find when called. If you add a new elemenent after the bind call, it will not receive the listener binding.

如果.link-in标记在页面加载后以语法形式插入到DOM中,则bind()方法将失败:bind()将侦听器附加到调用时找到的元素。如果在绑定调用后添加新的元素,它将不会收到侦听器绑定。

In order to prevent that when dinamically inserting html code in a page, you should use the on() method:

为了防止在页面中插入html代码时,应该使用on()方法:

  $('body').on('click' , '.link-in', function(e) {
     e.preventDefault();
     var pageIn = $(this).attr('href');
     loadPage(pageIn);
     return false;
  });

And now, every .link-in tag you push dinamically inside body will respond to the click listener. A discussion on using on() by default instead of bind() is in fact found in the bind() documentation.

而现在,你在体内推动的每个.link-in标签都会响应点击监听器。事实上,在bind()文档中可以找到关于默认使用on()而不是bind()的讨论。

#1