Asp。Net MVC从JQuery UI选项卡加载使用ajax的部分视图

I have several action methods on my controller that return a partial view (ascx), and I want these partial views to be rendered when clicking on the different JQuery UI tabs.

我的控制器上有几个操作方法，它们返回部分视图(ascx)，我希望在单击不同的JQuery UI选项卡时呈现这些部分视图。

The tabs are defined like this:

标签的定义如下:

<div id="tabs">
  <li><a href="#FirstTab" title="First tab">First tab</a></li>
  <li><%= Html.ActionLink("General", "General", new {id=Model.Id}) %></li>
  <li><%= Html.ActionLink("Details", "Details", new {id=Model.Id}) %></li>
  <div id="FirstTab">
  ...
  </div>
</div>

This renders the tabs fine, the first tab (with static content) is displayed correctly, but when I click the other tabs, nothing happens.

这样可以很好地呈现选项卡，第一个选项卡(带有静态内容)将被正确显示，但是当我单击其他选项卡时，什么也不会发生。

If instead of returning a partial view from the action methods I just return plain content, it renders the content just fine and the tabs work perfectly.

如果我不返回操作方法中的部分视图，而是返回纯内容，那么它就会使内容变得很好，选项卡也能很好地工作。

Any idea of what am I doing wrong?

你知道我做错了什么吗?

Thanks

谢谢

1 个解决方案

#1

Hey, I've done the same thing recently. I simplified in order to be more clear:

嘿，我最近也做过同样的事。我简化了，以便更清楚:

The html:

html:

    <div class="tabs">
              <ul>
                   <li>
                       <a onclick="TabItemClicked(this,<%=Url.Action("General", new {id=Model.Id}) %>))" href="#fragment1">
                       <span>General</span>
                       </a>
                   </li>
                   <li>
                       <a onclick="TabItemClicked(this,<%= Html.ActionLink("Details", new {id=Model.Id}) %>))" href="#fragment2">
                       <span>Details</span>
                       </a>
                   </li>
              </ul>
              <div id="fragment1"></div>
              <div id="fragment2"></div>
  </div>

and the JQuery code:

与JQuery代码:

function TabItemClicked(a, action) {

    var container = $(a).parents('div.tabs');
    var resultDiv = $($(a).attr('href'), container);

    $.ajax({
        type: "POST",
        url: action,
        data: {},
        success: function(response) {
            resultDiv.html('');
            resultDiv.html(response);
        }
    });
}

#1