如何获得两个字符之间的所有子字符串?

If I wanted to pull all substrings between two characters(general) along a String how would I do that? I also want to keep the first char I match but not the second one.

如果我想在两个字符(一般)之间拉出所有的子字符串，我该怎么做呢?我还希望保持第一个char I匹配，而不是第二个char。

So, for example, if I wanted ot keep the characters between a # char and either the next whitespace OR next of another char (in this case # again, but could be anything) and I had a string, say : "hello i'm #chilling#likeAVillain but like #forreal"

例如，如果我想在# char和下一个空格之间或者另一个char之间保持字符(在本例中是#，但是可以是任何东西)，我有一个字符串，比如:“你好，我是#chill #likeAVillain，但是像#forreal”

How would I get, say a Set of [#chilling, #likeAVillain, #forreal]

我怎么才能得到一套[# cold， #likeAVillain， #forreal]

I'm having difficulty because of the either/or end substring case - I want the substring starting with # and ending before the first occurence of either another # or a whitespace (or the end of the string if neither of those are found)

由于/或结束子字符串的情况，我遇到了困难——我希望以#开头的子字符串在另一个#或空格的第一次出现之前结束(或者字符串的末尾，如果两个都没有找到的话)

Put simplest in sudocode:

把简单的sudocode:

for every String W between [char A, either (char B || char C)) // notice [A,B) - want the 
                                                               //first to be inclusive
   Set.add(W);

2 个解决方案

#1

This regex #\\w+ seems to do what you need. It will find # and all alphanumeric characters after it. Since whitespace is not part of \\w it will not be included in your match.

这个regex #\ w+似乎可以满足您的需要。它会在后面找到#和所有字母数字字符。因为空格不是\w的一部分，所以不会包含在您的匹配中。

String s = "hello i'm #chilling#likeAVillain but like #forreal";
Pattern p = Pattern.compile("#\\w+");
Matcher m = p.matcher(s);
while (m.find())
    System.out.println(m.group());

output:

输出:

#chilling
#likeAVillain
#forreal

#2

public static void main(String[] args) throws Exception{

    String s1 = "hello i'm #chilling#likeAVillain but like #forreal";
    String[] strArr = s1.split("\\#");
    List<String> strOutputArr = new ArrayList<String>();
    int i = 0;
    for(String str: strArray){

        if(i>0){
            strOutputArray.add("#" + str.split("\\s+")[0]);
        }
        i++;
    }
    System.out.println(strOutputArray.toString());

    }