Let's say I work with the following table:
假设我使用下表：
ID LETTER VALUE
1 A NON-VALID
1 B VALID
1 C VALID
1 D VALID
2 A NON-VALID
2 B VALID
2 C NON-VALID
2 D VALID
So, what I want is simple, but I haven't found something similar or figured it out by myself.
所以，我想要的只是简单，但我没有找到类似的东西或自己想出来的东西。
I want to take the IDs that have let's say the value VALID in all the letters I will define.For example, if I want to have valid values on Bs and Cs, I want my data set to return ID 1.
我想在我将要定义的所有字母中使用可以说值VALID的ID。例如，如果我想在B和C上有有效值，我希望我的数据集返回ID 1。
Silly example:
愚蠢的例子：
SELECT ID
FROM table
WHERE VALUE=VALID IN EVERY ROW WHERE LETTER BETWEEN 'B' AND 'C'
1 个解决方案
#1
1
You can do something like this:
你可以这样做：
select id
from t
where letter in ('B', 'C') and value = 'Valid'
group by id
having count(distinct letter) = 2; -- "2" is the number of letters in your list
#1
1
You can do something like this:
你可以这样做：
select id
from t
where letter in ('B', 'C') and value = 'Valid'
group by id
having count(distinct letter) = 2; -- "2" is the number of letters in your list