如何验证动态angularJs表格

I have this following code:

我有以下代码:

<div class="table-responsive" ng-if="form.productDetails != false">
    <table class="table table-striped table-condensed table-hover">
        <thead>
            <tr class="small">
                <th class="col-xs-1">Name of Product/th>
                    <th class="col-xs-1">Price</th>
                    <th class="col-xs-1">Actions</th>
            </tr>
        </thead>

        <tbody>
            <tr ng-repeat="productDetails in form.productDetails.item">
                <td ng-form="prductForm"><input type="hidden"       name="productDetails" required ng-model="form.mainProductDetails.productDetails" ng-value="{{productDetails.name}}"></td>
                <td>{{productDetails.name}}</td>
                <td>{{productDetails.price}}</td>
                <td>
                    <button type="button" class="btn btn-xs btn-primary" ng-click="editProduct(productDetails)"><i class="glyphicon glyphicon-pencil"></i>&nbsp;Edit</button>

                    <button type="button" class="btn btn-xs btn-danger" ng-click="removeProduct(productDetails)"><i class="glyphicon glyphicon-trash"></i>&nbsp;Delete</button>
                </td>
            </tr>
        </tbody>
    </table>
</div>

Now I want to make the table or the columns required and table will be only validate if there is any data exists in the table columns.

现在，我要使表或列成为必需的，并且只有在表列中存在任何数据时，表才会被验证。

I have added this hidden input field which needs to be required. based on data passed from ng-repeat the validation should be done.

我添加了这个需要的隐藏输入字段。根据从ng-repeat传递的数据进行验证。

I have seen many examples but not quite sure how to solve this. Thanks in advance.

我见过很多例子，但不太确定如何解决这个问题。提前谢谢。

1 个解决方案

#1

Have you tried using ng-required in angularjs ? ng-required is to set an input field to required or not required dynamically. Also if possible could you share your code online so that I understand the problem statement properly.

你试过在angularjs中使用ng-required吗?ng-required是动态地将输入字段设置为required或not required。如果可能的话，您可以在网上共享您的代码，以便我正确地理解问题声明。