Google Maps API v3：如何删除事件侦听器？

How do I remove the 'bounds_changed' Event listener in Google Maps API v3?

如何在Google Maps API v3中删除'bounds_changed'事件侦听器？

google.maps.event.removeListener(_???_);

4 个解决方案

#1

139

Usually you can find answers to such questions in Google Maps API documentation.

通常，您可以在Google Maps API文档中找到此类问题的答案。

As Andrew said, addListener returns a handle which you can use later to remove the listener. That's because a single event can have many listeners and to remove them you must save a reference to each of attached listeners.

正如Andrew所说，addListener返回一个句柄，稍后您可以使用它来删除监听器。这是因为单个事件可以有许多侦听器并且要删除它们，您必须保存对每个连接侦听器的引用。

There's also a function which removes all of the listeners at the same time:

还有一个函数可以同时删除所有的侦听器：

clearListeners(instance:Object, eventName:string);
//In your case:
google.maps.event.clearListeners(map, 'bounds_changed');

Here's the Google Maps API reference where you can read about it.

这是Google Maps API参考，您可以在其中阅读相关信息。

#2

addListener returns a handle which you can later pass to removeListener:

addListener返回一个句柄，稍后您可以将其传递给removeListener：

var listenerHandle = google.maps.event.addListener(map, 'bounds_changed', function() {

google.maps.event.removeListener(listenerHandle);

#3

This seems to work in the current release.

这似乎适用于当前版本。

var listenerHandle = google.maps.event.addListener(map, 'bounds_changed', function() {
    // Handler code.
});
listenerHandle.remove();

#4

If you couldnt hold the listener object somehow you could remove listener(s) directly as google.maps.event.clearListeners(objectListened, 'event');

如果你不能以某种方式保持监听器对象，你可以直接删除监听器google.maps.event.clearListeners（objectListened，'event'）;

Ex: google.maps.event.clearListeners(map, 'bounds_changed');

例如：google.maps.event.clearListeners（map，'bounds_changed'）;

#1

139