sqlalchemy 多对多

时间:2022-01-06 05:11:24

一、表关系

class Student(Base):
    __tablename__ = student
    id = Column(Integer, primary_key=True)
    name = Column(String(32), index=True, nullable=False)

    course_list = relationship(Course, secondary=student2course, backref=student_list)

class Course(Base):
    __tablename__ = course
    id = Column(Integer, primary_key=True)
    title = Column(String(32), index=True, nullable=False)

class Student2Course(Base):
    __tablename__ = student2course
    id = Column(Integer, primary_key=True, autoincrement=True)
    student_id = Column(Integer, ForeignKey(student.id))
    course_id = Column(Integer, ForeignKey(course.id))

    __table_args__ = (
        UniqueConstraint(student_id, course_id, name=uix_stu_cou), # 联合唯一索引
        # Index(‘ix_id_name‘, ‘name‘, ‘extra‘),                          # 联合索引
    )

注意:要自己创建第三张表

二、操作数据

# 1. 创建一个课程,创建2学生,两个学生选新创建的课程。
obj = Course(title=英语)
obj.student_list = [Student(name=b),Student(name=c)]

session.add(obj)
session.commit()

# 2. 三张表join
ret = session.query(Student2Course.id,Student.name,Course.title).join(Student,Student2Course.student_id==Student.id,isouter=True).join(Course,Student2Course.course_id==Course.id,isouter=True).order_by(Student2Course.id.asc())
for row in ret:
    print(row)
# 3. “a”选的所有课
# 原生
ret = session.query(Student2Course.id,Student.name,Course.title).join(Student,Student2Course.student_id==Student.id,isouter=True).join(Course,Student2Course.course_id==Course.id,isouter=True).filter(Student.name==a).order_by(Student2Course.id.asc()).all()
print(ret)
# relation
obj = session.query(Student).filter(Student.name==a).first()
for item in obj.course_list:
    print(item.title)

# 4. 选了“生物”的所有人
obj = session.query(Course).filter(Course.title==生物).first()
for item in obj.student_list:
    print(item.name)