bzoj1212

时间:2023-12-19 21:24:23

trie树最基本的应用了
不难得到f[i]=f[j] if (s[j+1~i]∈dictionary);
可以用trie树匹配

 var can,f:array[..] of boolean;
son:array[..,..] of longint;
j,l,i,t,n,m,ans:longint;
ss:ansistring;
s:string; procedure add(s:string);
var i,l,p,x:longint;
begin
l:=length(s);
p:=;
for i:=l downto do
begin
x:=ord(s[i])-;
if son[p,x]=- then
begin
inc(t);
son[p,x]:=t;
end;
p:=son[p,x];
end;
can[p]:=true;
end; function ask(j:longint):boolean;
var i,p,x:longint;
begin
p:=;
while j> do
begin
x:=ord(ss[j])-;
if son[p,x]=- then exit(false);
p:=son[p,x];
dec(j);
if f[j] and can[p] then exit(true);
end;
exit(false);
end; begin
readln(n,m);
t:=;
fillchar(son,sizeof(son),);
for i:= to n do
begin
readln(s);
add(s);
end;
for i:= to m do
begin
readln(ss);
l:=length(ss);
fillchar(f,sizeof(f),false);
ans:=;
f[]:=true;
for j:= to l do
begin
f[j]:=ask(j);
if f[j] then ans:=j;
end;
writeln(ans);
end;
end.