大数的除法 不使用BigInteger Java实现

时间:2023-12-18 21:34:38
import java.util.Arrays;

public class Solution {
public void div(String a, String b) { char[] chara = a.toCharArray();
char[] charb = b.toCharArray();
int[] numa = new int[a.length()];
int[] numb = new int[b.length()];
for (int i = 0; i < charb.length; i++) {
numb[i] = charb[i]-'0';
// System.out.print(""+numb[i]);
}
System.out.println("");
for (int i = 0; i < chara.length; i++) {
numa[i] = chara[i]-'0';
System.out.print(""+numa[i]);
}
System.out.println("");
int[] div = new int [1000];
int count = 0;
while(compare(numa,numb)>0){
numa= div(numa,numb);
addSelf(div,count); }
StringBuffer sb = new StringBuffer();
sb.append(""+div+" ");
for (int i = 0; i < numa.length; i++) {
sb.append(""+numa[i]);
}
System.out.println(""+sb);
} private void addSelf(int[] div, int count) {
if (div[div.length-1]!=9) {
div[div.length-1]++;
}else{
int i = div.length-1;
while (div[i]==9){
div[i] = 0;
i--;
} ;
if (div[i]==0) {
count++;
}else{
div[i] ++;
} } } private int[] div(int[] numa, int[] numb) {
for (int i = 0; i < numb.length; i++) {
int tmpa = numa[numa.length-i-1];
int tmpb = numb[numb.length-i-1];
int sub = tmpa-tmpb;
int count = numa.length-1;
if (sub>=0) {
numa[numa.length-i-1] = sub;
}else{
numa[numa.length-i-1] = sub+10;
count =numa.length- i-1-1;
while(numa[count]==0){
numa[count] =9;
count--; }
numa[count]--;
if (numa[0]==0) {
numa = Arrays.copyOfRange(numa,1, numa.length); }
} } for (int i = 0; i < numa.length; i++) {
// System.out.print(""+numa[i]);
}
//System.out.println("");
return numa;
} int compare(int[] numa, int[] numb) {
if (numa.length<numb.length) {
return -1;
}else if (numa.length>numb.length) {
return 1;
}else{
for (int i = 0; i < numb.length; i++) {
if (numa[i]>numb[i]) {
return 1;
}
if (numa[i]<numb[i]) {
return -1;
}
}
return 0;
} }
public static void main(String[] args) {
Solution solution = new Solution();
String a = "1234578901234567890123456789";
String b = "1";
solution.div(a, b);
}
}