var data = [
{
"Id": 4,
"Created_at": "2017-11-04T15:47:17Z"
},
{
"Id": 5,
"Created_at": "2017-11-05T15:53:24Z"
},
{
"Id": 6,
"Created_at": "2017-11-05T18:59:32Z"
},
{
"Id": 7,
"Created_at": "2017-11-05T20:05:39Z"
}
]
I want above jsonaaray look like below structure. Without using loop will be best for me. I want the easiest one which help me to improve my experience. Would you please suggest me how can i solve this?
我想在jsonaaray之上看起来像下面的结构。不使用循环对我来说是最好的。我想要最简单的一个帮助我提高经验。你能告诉我怎么解决这个问题?
var data = [
{
"Id": 4,
"Created_at": "2017-11-04 15:47:17"
},
{
"Id": 5,
"Created_at": "2017-11-05 15:53:24"
},
{
"Id": 6,
"Created_at": "2017-11-05 18:59:32"
},
{
"Id": 7,
"Created_at": "2017-11-05 20:05:39Z"
}
]
3 个解决方案
#1
3
Using the function forEach
would be the cleanest way.
使用forEach函数将是最干净的方法。
var data = [{ "Id": 4, "Created_at": "2017-11-04T15:47:17Z"},{ "Id": 5, "Created_at": "2017-11-05T15:53:24Z"},{ "Id": 6, "Created_at": "2017-11-05T18:59:32Z"},{ "Id": 7, "Created_at": "2017-11-05T20:05:39Z"}];
data.forEach(d => d.Created_at = d.Created_at.replace('T', " ").replace("Z", ""));
console.log(data)
.as-console-wrapper { max-height: 100% !important; top: 0; }
#2
3
I'm sure there is a better date related solution, but you could easily use map() to loop through and remove the letters
我确信有一个更好的日期相关的解决方案,但你可以轻松地使用map()循环并删除字母
data.map(item => ({ Id: item.Id, Created_at: item.Created_at.replace(/T/g,' ').replace(/Z/g, '')}))
var data = [
{
"Id": 4,
"Created_at": "2017-11-04T15:47:17Z"
},
{
"Id": 5,
"Created_at": "2017-11-05T15:53:24Z"
},
{
"Id": 6,
"Created_at": "2017-11-05T18:59:32Z"
},
{
"Id": 7,
"Created_at": "2017-11-05T20:05:39Z"
}
]
console.log(data.map(item => ({ Id: item.Id, Created_at: item.Created_at.replace(/T/g,' ').replace(/Z/g, '')})))
#3
1
This will be the cleanest way:
这将是最干净的方式:
data.map(obj => {
return { Id: obj.Id, Created_at: obj.Created_at.slice(0, -1) }
})
#1
3
Using the function forEach
would be the cleanest way.
使用forEach函数将是最干净的方法。
var data = [{ "Id": 4, "Created_at": "2017-11-04T15:47:17Z"},{ "Id": 5, "Created_at": "2017-11-05T15:53:24Z"},{ "Id": 6, "Created_at": "2017-11-05T18:59:32Z"},{ "Id": 7, "Created_at": "2017-11-05T20:05:39Z"}];
data.forEach(d => d.Created_at = d.Created_at.replace('T', " ").replace("Z", ""));
console.log(data)
.as-console-wrapper { max-height: 100% !important; top: 0; }
#2
3
I'm sure there is a better date related solution, but you could easily use map() to loop through and remove the letters
我确信有一个更好的日期相关的解决方案,但你可以轻松地使用map()循环并删除字母
data.map(item => ({ Id: item.Id, Created_at: item.Created_at.replace(/T/g,' ').replace(/Z/g, '')}))
var data = [
{
"Id": 4,
"Created_at": "2017-11-04T15:47:17Z"
},
{
"Id": 5,
"Created_at": "2017-11-05T15:53:24Z"
},
{
"Id": 6,
"Created_at": "2017-11-05T18:59:32Z"
},
{
"Id": 7,
"Created_at": "2017-11-05T20:05:39Z"
}
]
console.log(data.map(item => ({ Id: item.Id, Created_at: item.Created_at.replace(/T/g,' ').replace(/Z/g, '')})))
#3
1
This will be the cleanest way:
这将是最干净的方式:
data.map(obj => {
return { Id: obj.Id, Created_at: obj.Created_at.slice(0, -1) }
})