IF语句正在更改函数中的数组元素

When my program runs, the IF ( ch[0] == 'P') actually puts the value 'P' into ch[0]. Any ideas what is happening here? The output is: "Array is Pyz"

当我的程序运行时，IF（ch [0] =='P'）实际上将值'P'放入ch [0]。有什么想法在这里发生了什么？输出是：“数组是Pyz”

char *try1(char ch[]);

int main()
{
  char ch[] = { 'x','y','z' }, *ch1;
  ch1=try1(ch); 
  printf("\nArray is %s\n",ch1);
  return 0;
}

char *try1 (char ch[])
{
  if (ch[0]=='P')
  {
    ch[1]='Q';
  }

  return ch;
}

1 个解决方案

#1

If you want to interpret ch as a string, you should terminate the array with '/0'. Replace

如果要将ch解释为字符串，则应使用“/ 0”终止数组。更换

char ch[] = { 'x','y','z'}

with

同

char ch[] = { 'x','y','z', '\0' }

and the output becomes "Array is xyz."

输出变为“Array is xyz”。

For more information, read https://en.wikipedia.org/wiki/Null-terminated_string

有关更多信息，请阅读https://en.wikipedia.org/wiki/Null-terminated_string

#1