使用beautifulsoup提取属性值

I am trying to extract the content of a single "value" attribute in a specific "input" tag on a webpage. I use the following code:

我试图在网页上的特定“输入”标签中提取单个“值”属性的内容。我使用以下代码：

import urllib
f = urllib.urlopen("http://58.68.130.147")
s = f.read()
f.close()

from BeautifulSoup import BeautifulStoneSoup
soup = BeautifulStoneSoup(s)

inputTag = soup.findAll(attrs={"name" : "stainfo"})

output = inputTag['value']

print str(output)

I get a TypeError: list indices must be integers, not str

我得到一个TypeError：列表索引必须是整数，而不是str

even though from the Beautifulsoup documentation i understand that strings should not be a problem here... but i a no specialist and i may have misunderstood.

即使从Beautifulsoup文档我明白字符串不应该是一个问题...但我不是专家，我可能会误解。

Any suggestion is greatly appreciated! Thanks in advance.

任何建议都非常感谢！提前致谢。

5 个解决方案

#1

.findAll() returns list of all found elements, so:

.findAll（）返回所有找到的元素的列表，因此：

inputTag = soup.findAll(attrs={"name" : "stainfo"})

inputTag is a list (probably containing only one element). Depending on what you want exactly you either should do:

inputTag是一个列表（可能只包含一个元素）。根据您的具体需要，您应该做：

 output = inputTag[0]['value']

or use .find() method which returns only one (first) found element:

或者使用.find（）方法，它只返回一个（第一个）找到的元素：

 inputTag = soup.find(attrs={"name": "stainfo"})
 output = inputTag['value']

#2

If you want to retrieve multiple values of attributes from the source above, you can use findAll and a list comprehension to get everything you need:

如果要从上面的源中检索多个属性值，可以使用findAll和list comprehension来获取所需的一切：

import urllib
f = urllib.urlopen("http://58.68.130.147")
s = f.read()
f.close()

from BeautifulSoup import BeautifulStoneSoup
soup = BeautifulStoneSoup(s)

inputTags = soup.findAll(attrs={"name" : "stainfo"})
### You may be able to do findAll("input", attrs={"name" : "stainfo"})

output = [x["stainfo"] for x in inputTags]

print output
### This will print a list of the values.

#3

I would actually suggest you a time saving way to go with this assuming that you know what kind of tags have those attributes.

假设您知道哪种标签具有这些属性，我实际上会建议您节省时间。

suppose say a tag xyz has that attritube named "staininfo"..

假设一个标签xyz有那个名为“staininfo”的attritube ..

full_tag = soup.findAll("xyz")

And i wan't you to understand that full_tag is a list

而且你不明白full_tag是一个列表

for each_tag in full_tag:
    staininfo_attrb_value = each_tag["staininfo"]
    print staininfo_attrb_value

Thus you can get all the attrb values of staininfo for all the tags xyz

因此，您可以获取所有标签xyz的staininfo的所有attrb值

#4

In Python 3.x, simply use get(attr_name) on your tag object that you get using find_all:

在Python 3.x中，只需在使用find_all获取的标记对象上使用get（attr_name）：

xmlData = None

with open('conf//test1.xml', 'r') as xmlFile:
    xmlData = xmlFile.read()

xmlDecoded = xmlData

xmlSoup = BeautifulSoup(xmlData, 'html.parser')

repElemList = xmlSoup.find_all('repeatingelement')

for repElem in repElemList:
    print("Processing repElem...")
    repElemID = repElem.get('id')
    repElemName = repElem.get('name')

    print("Attribute id = %s" % repElemID)
    print("Attribute name = %s" % repElemName)

against XML file conf//test1.xml that looks like:

针对XML文件conf // test1.xml，它看起来像：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root>
    <singleElement>
        <subElementX>XYZ</subElementX>
    </singleElement>
    <repeatingElement id="11" name="Joe"/>
    <repeatingElement id="12" name="Mary"/>
</root>

prints:

打印：

Processing repElem...
Attribute id = 11
Attribute name = Joe
Processing repElem...
Attribute id = 12
Attribute name = Mary

#5

you can also use this :

你也可以用这个：

import requests
from bs4 import BeautifulSoup
import csv

url = "http://58.68.130.147/"
r = requests.get(url)
data = r.text

soup = BeautifulSoup(data, "html.parser")
get_details = soup.find_all("input", attrs={"name":"stainfo"})

for val in get_details:
    get_val = val["value"]
    print(get_val)

#1