从PHP中的DOMElement获取特定的子标记

I am walking through a xml definition file and I have a DOMNodeList that I am walking through. I need to extract the contents of a child tag that may or may not be in the current entity

我正在浏览一个xml定义文件，我有一个DOMNodeList，我正在浏览。我需要提取子标记的内容，这个子标记可能在当前实体中，也可能不在当前实体中

<input id="name">
  <label>Full Name:</label>
  <required />
</input>
<input id="phone">
  <required />
</input>
<input id="email" />

I need to replace ????????????? with something that gets me the contents of the label tag if it exists.

我需要更换???????????如果标签的内容存在的话，我就可以得到标签的内容。

Code:

代码:

foreach($dom->getElementsByTagName('required') as $required){
  $curr = $required->parentNode;

  $label[$curr->getAttribute('id')] = ?????????????
}

Expected Result:

预期结果:

Array(
  ['name'] => "Full Name:"
  ['phone'] => 
)

1 个解决方案

#1

Strange thing is: you already know the answer since you've used it in your script, getElementsByTagName().
But this time not with the DOMDocument as context "node" but with the input DOMElement:

奇怪的是:您已经知道答案了，因为您已经在脚本getElementsByTagName()中使用了它。但这一次不使用DOMDocument作为上下文“节点”，而是使用输入DOMElement:

<?php
$doc = getDoc();
foreach( $doc->getElementsByTagName('required') as $e ) {
  $e = $e->parentNode; // this should be the <input> element
  // all <label> elements that are direct children of this <input> element
  foreach( $e->getElementsByTagName('label') as $l ) {
    echo 'label="', $l->nodeValue, "\"\n";
  }
}

function getDoc() {
  $doc = new DOMDocument;
  $doc->loadxml('<foo>
    <input id="name">
      <label>Full Name:</label>
      <required />
    </input>
    <input id="phone">
      <required />
    </input>
    <input id="email" />
  </foo>');
  return $doc;
}

prints label="Full Name:"

打印标签= "姓名:"

#1