PHP数组的stdClass，如何获取数据？

I would like to print the value of [name]. I am just becoming familiar with standard defined classes and how they are called.

我想打印[name]的值。我只是熟悉标准定义的类以及如何调用它们。

Based on this example and logic

基于这个例子和逻辑

$arrayobj = new ArrayObject(array('first','second','third'));
print_r($arrayobj);
//outputs: ArrayObject Object ( [0] => first [1] => second [2] => third )

With that. I'm trying to extract the value of name (Pebbles) out of here.

接着就，随即。我试图从这里提取名称（Pebbles）的值。

print_r($terms);
/* outputs
Array ( [3] => stdClass Object ( [term_id] => 3 [name] => Pebbles ) )
*/

So I tried

所以我试过了

echo $terms[0]->name;

Got peanuts. How do I do this?

有花生。我该怎么做呢？

4 个解决方案

#1

The only array key listed is [3] (Array ( [3] => stdClass...), so use

列出的唯一数组键是[3]（Array（[3] => stdClass ...），所以使用

echo $terms[3]->name;

Even though it is a numerically indexed array, that doesn't mean it starts with an index of 0 or even has sequential keys.

尽管它是一个数字索引的数组，但这并不意味着它以索引0开始，甚至不具有顺序键。

Get them all with a loop:

通过循环获取所有内容：

foreach ($terms as $t) {
   echo $t->name;
}

#2

Correct me if I am wrong, but you can typecast them.

如果我错了，请纠正我，但你可以对它们进行类型转换。

$terms = (array) $terms;

Will make it a normal array accessible through:

将通过以下方式使其成为正常的数组：

$terms[3]['name']

#3

You can use the following :

您可以使用以下内容：

echo $terms[3]->name ;

#4

To display the value of the objects fiel name, you can use this command:

要显示对象名称的值，可以使用以下命令：

    echo $this[3]->name;

#1