如何在while循环中获取所有用户输入并将它们放入print语句中

public class lsjdflsjdf {
public static void main(String[] args) {
    Scanner s = new Scanner(System.in);
    int input, sum = 0, count = 0;
    System.out.print("Enter a positive integer number: ");
    input = s.nextInt();

    while (input != -1) {
        count++;
        sum += input;
        System.out.print("Enter a positive integer number: ");
        input = s.nextInt();
    }

    System.out.println("Entered Number:\t" + count);
    System.out.println("The Sum:\t\t" + sum);
}

}

How do I take all the inputs so they can be displayed in the "Entered Number" println statement at the end so it would display such as:

如何获取所有输入,以便它们可以显示在最后的“输入数字”println语句中,以便显示如下:

   Entered Number:  10, 2, 13, 50, 100
   The Sum:         175

   Entered Number:  1, 2, 3, 4, 5, 6, 7, 8, 9, 10
   The Sum:         48

   Entered Number:  1, 1, 1, 1, 100
   The Sum:         104

   Entered Number:  0, 0, 0, 0, 0, 100
   The Sum:         100

1 个解决方案

#1

Get rid of count and replace it with a String which will report the numbers that have been entered. A simplistic solution would be to concatenate the new inputs with the existing output in your while loop.

摆脱计数并用一个字符串替换它,该字符串将报告已输入的数字。一个简单的解决方案是将新输入与while循环中的现有输出连接起来。

For example:

public static void main(String[] args) {
    Scanner s = new Scanner(System.in);
    int input, sum = 0;
    System.out.print("Enter a positive integer number: ");
    input = s.nextInt();

        String outputString = ""; //our result string

    while (input != -1) {
            outputString += input + " "; //adding to the output string
            sum += input;
            System.out.print("Enter a positive integer number: ");
            input = s.nextInt();
    }

    System.out.println("Entered Number:\t" + outputString);
    System.out.println("The Sum:\t\t" + sum);
}

You could also use StringBuilder to build up your output String.

您还可以使用StringBuilder来构建输出String。

#1