nodejs调用API并在响应中返回该API

I am very new to nodejs, and I am using restify to create routes, and one of the routes, I call another API, whose response I want to send back.

我是nodejs的新手，我正在使用restify创建路由，其中​​一条路由，我称之为另一个API，我希望将其回复。

server.get({path:'/admin'},
            function respond(req, res, next){
            var options = { method: 'GET',
                  url: argv.OKTA + "/api/v1/apps/" + argv.OKTA_APP_ID,
                  headers:
                   { authorization: argv.OKTA_API,
                     'content-type': 'application/json',
                     accept: 'application/json' } };

            request(options, function (error, response, body) {
                if (error) throw new Error(error);

                res.send(200, body);
                return next();
            });

});

So, if a GET is done on the /admin path, it should go and call another URL, and get the response back and use that as a response back to the /admin

因此，如果在/ admin路径上完成了GET，它应该去调用另一个URL，然后获取响应，并将其作为响应返回给/ admin

Right now, I get this instead:

现在，我得到了这个：

{"code":"ResourceNotFound","message":"/admin does not exist"}

1 个解决方案

#1

Since you're sending a response, you should not call next() (that calls the next middleware, which will end up at your 404 middleware).

由于您正在发送响应，因此不应调用next（）（调用下一个中间件，最终将在您的404中间件中）。