从php数组传递参数到构造函数[复制]

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• How to “invoke” a class instance in PHP? 3 answers
• 如何在PHP中“调用”类实例?3答案

Normally, if I want to pass arguments from $myarray to $somefunction I can do this in php using

通常，如果我想要将参数从$myarray传递到$somefunction，我可以在php中使用

call_user_func_array($somefunction, $myarray);

However this does not work when the function one wishes to call is the constructor for an object. For fairly obvious reasons it does not work to do:

然而，当你想要调用的函数是对象的构造函数时，这种方法就不起作用了。由于相当明显的原因，它不起作用:

$myobj = new call_user_func_array($classname, $myarray);

is there something fairly elegant that does work ?

有什么东西是相当优雅的吗?

1 个解决方案

#1

You can use the Reflection API:

您可以使用反射API:

• ReflectionClass::newInstanceArgs — Creates a new class instance from given arguments.
• 反射类::newInstanceArgs -从给定的参数创建一个新的类实例。

Example:

例子:

$reflector = new ReflectionClass('Foo');
$foo = $reflector->newInstanceArgs(array('foo', 'bar'));