如何从外部URL获取JSON数据?

时间:2021-09-28 20:19:30

A company that I am working with has an API for their Privacy Policy and Terms of Use. I need to create two different pages...one for the Privacy Policy and one for the Terms of Use. I'm pretty new at this, and I feel like I'm so close.

我正在与之合作的公司拥有其隐私政策和使用条款的API。我需要创建两个不同的页面...一个用于隐私策略,一个用于使用条款。我对此非常陌生,我觉得我很亲密。

Here is the way that the JSON is received (with some edits to anonymize it):

以下是接收JSON的方式(通过一些编辑对其进行匿名化):

{"code":200,"status":"Ok","data":
    {"offset":0,"limit":20,"total":2,"target":"html_page","results":[
        {
            "id":"6",
            "title":"Privacy Policy",
            "description":"Privacy Policy",
            "html":"HTML CODE BLAH BLAH",
            "tags":["privacy"]
        },
        {
            "id":"66",
            "title":"License and TOU",
            "description":"Terms of Use",
            "html":"HTML CODE BLAH BLAH",
            "tags":["terms"]
        }]
    }
}

Here's the code I'm using:

这是我正在使用的代码:

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8" />
<title>Privacy Policy</title>
</head>
<body>
    <div id="placeholder"></div>
    <script src="http://code.jquery.com/jquery-1.7.1.min.js"></script>
    <script>
    $.getJSON('http://externalurl.com', function(external) {
        var output="<ul>";
        for (var i in external.code.offset) {
            output+="<li>" + external.html + "</li>";
        }

        output+="</ul>";
        document.getElementById("placeholder").innerHTML=output;
  });
    </script>
</body>
</html>

It's just returning a blank page. What am I doing wrong?

它只是返回一个空白页面。我究竟做错了什么?

2 个解决方案

#1


3  

$.getJSON('http://externalurl.com', function(external) {
        var output = $("<ul />");

        $.each(external.data.results, function(i, result) {
             $('<li />', {text : result.html}).appendTo(output);
        });

        $('#placeholder').html(output);
});

#2


0  

I think it should be:

我认为它应该是:

$.getJSON('http://externalurl.com', function(external) {
    var output="<ul>";
    for (var i = 0; i < external.data.results.length; i++) {
        output+="<li>" + external.data.results[i].html + "</li>";
    }

    output+="</ul>";
    document.getElementById("placeholder").innerHTML=output;
});

So first you are iterating over the wrong object, it's external.data.results and not external.code.offset. Second, you can't iterate over an array with for (var i in array).

所以首先你要遍历错误的对象,它是external.data.results而不是external.code.offset。其次,您无法使用for(数组中的var i)迭代数组。

#1


3  

$.getJSON('http://externalurl.com', function(external) {
        var output = $("<ul />");

        $.each(external.data.results, function(i, result) {
             $('<li />', {text : result.html}).appendTo(output);
        });

        $('#placeholder').html(output);
});

#2


0  

I think it should be:

我认为它应该是:

$.getJSON('http://externalurl.com', function(external) {
    var output="<ul>";
    for (var i = 0; i < external.data.results.length; i++) {
        output+="<li>" + external.data.results[i].html + "</li>";
    }

    output+="</ul>";
    document.getElementById("placeholder").innerHTML=output;
});

So first you are iterating over the wrong object, it's external.data.results and not external.code.offset. Second, you can't iterate over an array with for (var i in array).

所以首先你要遍历错误的对象,它是external.data.results而不是external.code.offset。其次,您无法使用for(数组中的var i)迭代数组。