无法从单选按钮获取价值

I want to get the data from radio button when I submit it, but I don't know why I can't get the value from radio it.

我想在提交时从单选按钮获取数据,但我不知道为什么我无法从无线电中获取它的价值。

My code

<?php
   $choice = $_GET['choice'];
?>

<html>
<head>
</head>
<body>
    <form action="index.php" method="POST">
    <table align="center">
        <tr><td>Please select</td></tr>
        <tr><td><input type="radio" name="choice" value="0">aaaa</td></tr>
        <tr><td><input type="radio" name="choice" value="1">bbbb</td></tr>
        <tr><td><input type="radio" name="choice" value="2">cccc</td></tr>
        <tr><td><input type="radio" name="choice" value="3">dddd</td></tr>
        <tr><td><input type="submit" value="submit"></td></tr>
    </table>
             <?php echo"$choice";?>
    </form>
</body>
</html>

5 个解决方案

#1

Use $_POST Instead of $_GET to get data from form. Or you can use $_REQUEST also.Replace $_GET['choice'] with $_POST['choice'] or $_REQUEST['choice'].

使用$ _POST而不是$ _GET从表单中获取数据。或者您也可以使用$ _REQUEST还使用$ _POST ['choice']或$ _REQUEST ['choice']来替换$ _GET ['choice']。

#2

You are using $_GET, but the form is posted. Use $choice = $_POST['choice'].

您正在使用$ _GET,但表单已发布。使用$ choice = $ _POST ['choice']。

#3

Your form is POST but you're looking for it in $_GET[]. Look for it in $_POST['choice'] instead.

您的表单是POST,但您在$ _GET []中查找它。在$ _POST ['choice']中寻找它。

#4

The method of your form element should match the variable you access for the form data:

表单元素的方法应该与您为表单数据访问的变量匹配:

<form method="post">
// Need to use the $_POST[] array  to access values

<form method="get">
// Use the $_GET[] array to access values

$_GET is typically used for url strings. Usually you will want the method of your form to be post.

$ _GET通常用于url字符串。通常,您需要发布表单的方法。

#5

If your form has attribute method set to POST, than you should use _POST global array like this - <?php $choice = $_POST['choice']; ?>

如果你的表单将属性方法设置为POST,那么你应该像这样使用_POST全局数组 -

#1