Java多线程实战之交叉打印的两种方法

要求效果：先打印5次“printa…”，再打印5次“printb…”，每次打印间隔1秒，重复循环20次

方式一：使用wait()和notifyall()方法

public class myservice {
 private volatile boolean flag = false;
 public synchronized void printa() {
 try {
  while (flag) {
  wait();
  }
  for (int i = 0; i < 5; i++) {
  system.out.println("printa...");
  timeunit.seconds.sleep(1);
  }
  flag = true;
  notifyall();
 } catch (interruptedexception e) {
  e.printstacktrace();
 }
 }
 public synchronized void printb() {
 try {
  while (!flag) {
  wait();
  }
  for (int i = 0; i < 5; i++) {
  system.out.println("printb...");
  timeunit.seconds.sleep(1);
  }
  flag = false;
  notifyall();
 } catch (interruptedexception e) {
  e.printstacktrace();
 }
 }
}

public class backupa implements runnable {
 private myservice myservice;
 public backupa(myservice myservice) {
 super();
 this.myservice = myservice;
 }
 @override
 public void run() {
 myservice.printa();
 }
}

public class backupb implements runnable {
 private myservice myservice;
 public backupb(myservice myservice) {
 super();
 this.myservice = myservice;
 }
 @override
 public void run() {
 myservice.printb();
 }
}

public class run {
 public static void main(string[] args) {
 myservice myservice = new myservice();
 for (int i = 0; i < 20; i++) {
  new thread(new backupa(myservice)).start();
  new thread(new backupb(myservice)).start();
 }
 }
}

方式二：使用await()和signalall()方法

public class myservice {
 private lock lock = new reentrantlock();
 private condition condition = lock.newcondition();
 private boolean flag = false;
 public void printa() {
 try {
  lock.lock();
  while (flag) {
  condition.await();
  }
  for (int i = 0; i < 5; i++) {
  system.out.println("printa...");
  timeunit.seconds.sleep(1);
  }
  flag = true;
  condition.signalall();
 } catch (interruptedexception e) {
  e.printstacktrace();
 } finally {
  lock.unlock();
 }
 }
 public void printb() {
 try {
  lock.lock();
  while (!flag) {
  condition.await();
  }
  for (int i = 0; i < 5; i++) {
  system.out.println("printb...");
  timeunit.seconds.sleep(1);
  }
  flag = false;
  condition.signalall();
 } catch (interruptedexception e) {
  e.printstacktrace();
 } finally {
  lock.unlock();
 }
 }
}

public class threada implements runnable {
 private myservice myservice;
 public threada(myservice myservice) {
 super();
 this.myservice = myservice;
 }
 @override
 public void run() {
 myservice.printa();
 }
}

public class threadb implements runnable {
 private myservice myservice;
 public threadb(myservice myservice) {
 super();
 this.myservice = myservice;
 }
 @override
 public void run() {
 myservice.printb();
 }
}

public class run {
 public static void main(string[] args) {
 myservice myservice = new myservice();
 for (int i = 0; i < 20; i++) {
  new thread(new threada(myservice)).start();
  new thread(new threadb(myservice)).start();
 }
 }
}

总结

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原文链接：https://blog.csdn.net/qq_40378034/article/details/86766001