如何在mysql中获取最大值的最大值？

I have a schema like the following

我有一个如下的架构

id (INT)
Cycle_Number (INT)
Cycle_Day (INT)
Date (date)

...other columns irrelevant to the question...

How can I get the row that has the max Cycle_Day within the max Cycle_Number

如何在最大Cycle_Number内获得具有最大Cycle_Day的行

For example, say I have the following data

例如，假设我有以下数据

ID Cycle_Number Cycle_Day Date
1  1            1         2011-12-01
2  1            2         2011-12-02
3  2            1         2011-12-03
4  2            2         2011-12-04
5  2            3         2011-12-05
6  2            4         2011-12-06
7  3            1         2011-12-07
8  3            2         2011-12-08
9  3            3         2011-12-09

The query would return row 9. (It has the highest Cycle_Day within the highest Cycle_Number)

查询将返回第9行。（它具有最高Cycle_Number内的最高Cycle_Day）

Thanks

谢谢

2 个解决方案

#1

this one is compatible MySql 5.5 with no joint tables

这个兼容MySql 5.5没有联合表

SELECT id
FROM cycles
ORDER BY Cycle_Number DESC , Cycle_Day DESC
LIMIT 0 , 1

Regards

问候

#2

This SQL query should provide the max value you want.

此SQL查询应提供所需的最大值。

SELECT ID, Cycle_Number, Cycle_Day, Date
FROM  yourTable AS t
CROSS JOIN (
  SELECT MAX(Cycle_Number) AS Cycle_Number FROM yourTable
) AS sq USING (Cycle_Number)
ORDER BY Cycle_Day DESC LIMIT 1

#1