如何过滤嵌套在数组对象属性中的对象数组?

时间:2022-09-25 08:02:43

I have model like this:

我有这样的模型:

var model = [{id: 1, prices: [{count: 2}, {count: 3}]}, {id: 2, prices: [{count: 2}]}, {id: 3, prices: [{count: 3}]}];

var model = [{id:1,price:[{count:2},{count:3}]},{id:2,price:[{count:2}]},{id:3,price:[ {count:3}]}];

and I need to filter this objects of array useing property count and I will need to return matched objects in three scenarios:

我需要过滤数组使用属性计数的这些对象,我需要在三种情况下返回匹配的对象:

  1. if the objects have two objects in array prices,
  2. 如果对象在数组价格中有两个对象,

  3. if the objects have one object in array prices matching count:2,
  4. 如果对象在数组中有一个对象匹配count:2,

  5. if the objects have one property in array prices matching count:3.
  6. 如果对象在数组中的一个属性匹配count:3。

so..when i click the button without assigned value i wanna see all objects, when i click button with value = 2 i wanna see objects with count: 2 and when i click the button with value = 3 i wanna get objects with count: 3, i must do this in AngularJS –

所以......当我点击没有指定值的按钮时,我想要看到所有对象,当我点击值为2的按钮时,我想看到带有计数的对象:2,当我点击值为3的按钮时,我想得到带有计数的对象: 3,我必须在AngularJS中做到这一点 -

3 个解决方案

#1


0  

maybe something like this?

也许是这样的?

var result = model.filter(function(m) {
   // make sure the m.prices field exists and is an array
   if (!m.prices || !Array.isArray(m.prices)) {
       return false;
   }

   var numOfPrices = m.prices.length

   if (numOfPrices === 2) { // return true if its length is 2
       return true;
   }

   for (var i = 0; i < numOfPrices; i++) {
       if (m.prices[i].count && 
           (m.prices[i].count === 2 || 
            m.prices[i].count == 3)) {
            return true;
        }
    }

    return false;
});

#2


0  

use lodash or underscore library.. and then your code with lodash will be like:

使用lodash或下划线库..然后你的代码与lodash将是:

_.filter(model, function(i){
   return _.intersection(_.map(i.prices, 'count'), [3,2]).length;
})

it returns items that on their price property have array which contains element with count = 3 or count = 2

它返回其price属性上的项目包含count = 3或count = 2的元素的数组

#3


0  

var model = [{
    id: 1,
    prices: [{
        count: 2
    }, {
        count: 3
    }]
}, {
    id: 2,
    prices: [{
        count: 2
    }]
}, {
    id: 3,
    prices: [{
        count: 3
    }]
}];

var search = function(data) {
    var result = {};

    function arrayObjectIndexOf(myArray, searchTerm, property) {
        for (var i = 0, len = myArray.length; i < len; i++) {
            if (myArray[i][property] === searchTerm) return i;
        }
        return -1;
    }

    for (var index in data) {
        if (data[index].hasOwnProperty("prices") && arrayObjectIndexOf(data[index].prices, 2, 'count') != -1) {
            result[data[index].id] = data[index];
        } else if (data[index].hasOwnProperty("prices") && arrayObjectIndexOf(data[index].prices, 3, 'count') != -1) {
            result[data[index].id] = data[index];
        } else if (data[index].hasOwnProperty("prices") &&
            data[index].prices.length == 2) {
            result[data[index].id] = data[index];
        }

    }

    return result;
}
var output = search(model);
console.log(output);

#1


0  

maybe something like this?

也许是这样的?

var result = model.filter(function(m) {
   // make sure the m.prices field exists and is an array
   if (!m.prices || !Array.isArray(m.prices)) {
       return false;
   }

   var numOfPrices = m.prices.length

   if (numOfPrices === 2) { // return true if its length is 2
       return true;
   }

   for (var i = 0; i < numOfPrices; i++) {
       if (m.prices[i].count && 
           (m.prices[i].count === 2 || 
            m.prices[i].count == 3)) {
            return true;
        }
    }

    return false;
});

#2


0  

use lodash or underscore library.. and then your code with lodash will be like:

使用lodash或下划线库..然后你的代码与lodash将是:

_.filter(model, function(i){
   return _.intersection(_.map(i.prices, 'count'), [3,2]).length;
})

it returns items that on their price property have array which contains element with count = 3 or count = 2

它返回其price属性上的项目包含count = 3或count = 2的元素的数组

#3


0  

var model = [{
    id: 1,
    prices: [{
        count: 2
    }, {
        count: 3
    }]
}, {
    id: 2,
    prices: [{
        count: 2
    }]
}, {
    id: 3,
    prices: [{
        count: 3
    }]
}];

var search = function(data) {
    var result = {};

    function arrayObjectIndexOf(myArray, searchTerm, property) {
        for (var i = 0, len = myArray.length; i < len; i++) {
            if (myArray[i][property] === searchTerm) return i;
        }
        return -1;
    }

    for (var index in data) {
        if (data[index].hasOwnProperty("prices") && arrayObjectIndexOf(data[index].prices, 2, 'count') != -1) {
            result[data[index].id] = data[index];
        } else if (data[index].hasOwnProperty("prices") && arrayObjectIndexOf(data[index].prices, 3, 'count') != -1) {
            result[data[index].id] = data[index];
        } else if (data[index].hasOwnProperty("prices") &&
            data[index].prices.length == 2) {
            result[data[index].id] = data[index];
        }

    }

    return result;
}
var output = search(model);
console.log(output);