I am getting the following error while migrating VC6 code to VS2008. This code works fine in VC6 but gives a compilation error in VC9. I know it is because of a compiler breaking change. What is the problem and how do I fix it?
我将VC6代码迁移到VS2008时收到以下错误。此代码在VC6中工作正常,但在VC9中给出了编译错误。我知道这是因为编译器破坏了变化。有什么问题,我该如何解决?
error C2440: 'initializing' : cannot convert
from 'std::_Vector_iterator<_Ty,_Alloc>'
to 'STRUCT_MUX_NOTIFICATION *'
Code
MUX_NOTIFICATION_VECTOR::iterator MuxNotfnIterator;
for(
MuxNotfnIterator = m_MuxNotfnCache.m_MuxNotificationVector.begin();
MuxNotfnIterator != m_MuxNotfnCache.m_MuxNotificationVector.end();
MuxNotfnIterator ++
)
{
STRUCT_MUX_NOTIFICATION *pstMuxNotfn = MuxNotfnIterator; //Error 2440
}
3 个解决方案
#1
If it worked before, I am guessing MUX_NOTIFICATION_VECTOR is a typedef
如果之前有效,我猜MUX_NOTIFICATION_VECTOR是一个typedef
typedef std::vector<STRUCT_MUX_NOTIFICATION> MUX_NOTIFICATION_VECTOR;
The iterator for a container can often be mistaken with a pointer (because it works the same way) and, in the case of some stl implementations, it can actually be a pointer (it probably was the case with STL provided with VC6). But there is no guarantee about that.
容器的迭代器通常可以用指针错误(因为它以相同的方式工作),并且在某些stl实现的情况下,它实际上可以是指针(可能是随VC6提供的STL的情况)。但是不能保证这一点。
What you should do is the following :
你应该做的是以下几点:
STRUCT_MUX_NOTIFICATION& reference = *MuxNotfnIterator;
// or
STRUCT_MUX_NOTIFICATION* pointer = &(*MuxNotfnIterator);
#2
I think this should do the trick:
我认为这应该做的伎俩:
STRUCT_MUX_NOTIFICATION *pstMuxNotfn = &(*MuxNotfnIterator);
#3
You'll need to dereference the iterator to get the appropriate struct (not sure why it worked before?):
您需要取消引用迭代器以获取相应的结构(不确定它之前的原因是什么?):
STRUCT_MUX_NOTIFICATION *pstMuxNotfn = *MuxNotfnIterator;
#1
If it worked before, I am guessing MUX_NOTIFICATION_VECTOR is a typedef
如果之前有效,我猜MUX_NOTIFICATION_VECTOR是一个typedef
typedef std::vector<STRUCT_MUX_NOTIFICATION> MUX_NOTIFICATION_VECTOR;
The iterator for a container can often be mistaken with a pointer (because it works the same way) and, in the case of some stl implementations, it can actually be a pointer (it probably was the case with STL provided with VC6). But there is no guarantee about that.
容器的迭代器通常可以用指针错误(因为它以相同的方式工作),并且在某些stl实现的情况下,它实际上可以是指针(可能是随VC6提供的STL的情况)。但是不能保证这一点。
What you should do is the following :
你应该做的是以下几点:
STRUCT_MUX_NOTIFICATION& reference = *MuxNotfnIterator;
// or
STRUCT_MUX_NOTIFICATION* pointer = &(*MuxNotfnIterator);
#2
I think this should do the trick:
我认为这应该做的伎俩:
STRUCT_MUX_NOTIFICATION *pstMuxNotfn = &(*MuxNotfnIterator);
#3
You'll need to dereference the iterator to get the appropriate struct (not sure why it worked before?):
您需要取消引用迭代器以获取相应的结构(不确定它之前的原因是什么?):
STRUCT_MUX_NOTIFICATION *pstMuxNotfn = *MuxNotfnIterator;