只将相等属性的值从一个JSON复制到另一个JSON

There is any way to copy only the value of equal properties from one JSON to another?
For example:

有没有办法只将相等属性的值从一个JSON复制到另一个JSON ?例如:

json1-

json1 -

{
  "isMultiRow": true,
  "name": "Donny",
  "description": "Donnyboy"
}

json2-

json2 -

{
  "isMultiRow": false,
  "name": "Jonny",
  "description": "Jonny boy"
  "age": "old"
  "radius":"big"
}

if I do something like json1.copy(json2) I'll get at json1 -

如果我做一些类似json1.copy(json2)的事情，我会在json1 -

{
  "isMultiRow": false,
  "name": "Jonny",
  "description": "Jonny boy"
}

age and radius won't appear because they don't exist in json1.

年龄和半径不会出现，因为它们在json1中不存在。

2 个解决方案

#1

You can either write a custom method that accepts 2 JSONObject and a list of fields that needs to be copied from one src JSONObject to dest JSONObject.

您可以编写一个接受2个JSONObject的自定义方法，以及需要从一个src JSONObject复制到dest JSONObject的字段列表。

private static void copy(JSONObject dest, JSONObject src, List<String> fields) {
    for (String key : fields) {
        dest.put(key, src.get(key));
    }
}

Or you can have your own custom class that extends JSONObject and have a new method copy that accepts another JSON and copies field by field.

或者，您可以有自己的自定义类来扩展JSONObject，并有一个接受另一个JSON的新方法副本，并逐个字段地复制。

public class JSON extends JSONObject {

    private static final long serialVersionUID = 1L;

    public void copy(JSON other) {
        // implement copy logic by iterating over keySet etc
    }
}

NOTE: If your JSON has simple key-values then above will be very simple implementation, if your JSON string has complex objects, arrays etc then you would have add handling for each of those types and do a deep copy/override from src to dest.

注意:如果您的JSON有简单的键值，那么上面的实现将非常简单，如果您的JSON字符串有复杂的对象、数组等等，那么您将需要为这些类型添加处理，并从src到dest执行深度复制/覆盖。

#2

Assuming the type of your JSON object implements Map, you can do this:

假设您的JSON对象的类型实现映射，您可以这样做:

json1.replaceAll(json2::getOrDefault);

This will replace fields in json1 with their corresponding values from json2. If json2 doesn't have a given field, it will be left as is.

这将用json1中的相应值替换json2中的字段。如果json2没有给定的字段，它将保持原样。

#1