当存在多个括号时，使用正则表达式提取特定括号内的信息

I have a file that contains this:

我有一个包含这个的文件：

dependencies {
    compile group: "org.osgi", name: "org.osgi.compendium", version: "5.0.0"
    compile group: "org.osgi", name: "org.osgi.core", version: "6.0.0"
}

deploy {
    deployDir = file("${Home}/osgi/modules")
}

and I want to extract the information inside dependencies bracket.

我想提取依赖项括号内的信息。

When I tried to use dependencies.*[^}] I would get everything except the close bracket for deploy.

当我尝试使用依赖项。* [^}]我会得到除了用于部署的关闭括号之外的所有内容。

How can I get the regex to stop at the first encounter of close bracket?

如何在第一次遇到紧密支架时让正则表达式停止？

3 个解决方案

#1

Use a non-greedy search

使用非贪婪的搜索

dependencies.*?[^}]}

#2

You can use a negated character class [^}] with a * quantifier to get to the closing brace, and just use } to match it as a literal symbol (it does not need escaping):

您可以使用带有*量词的否定字符类[^}]来获得结束括号，并使用}将其匹配为文字符号（它不需要转义）：

dependencies[^}]*}

See regex demo

请参阅正则表达式演示

No need for any look-arounds here that only hamper regex performance.

这里不需要任何只能阻碍正则表达式性能的环境。

#3

Simple to understand way is to match non-close braces:

简单易懂的方法是匹配非紧密的大括号：

(?<=dependencies \{)[^}]*

This has the advantage of not requiring the dot all flag (that makes dot match newlines).

这样做的好处是不需要dot all标志（这使得点匹配换行符）。

You also don't have to worry, or understand, or use, greedy/reluctant quantifiers.

您也不必担心，理解或使用贪婪/不情愿的量词。

The use of the look behind means that the entire match (not a captured group) is your target.

使用后面的外观意味着整个匹配（不是捕获的组）是您的目标。

#1