如何将字符串拆分为多个部分?

时间:2022-09-13 14:22:13

I have a string with several words separated by spaces, e.g. "firstword second third", and an ArrayList. I want to split the string into several pieces, and add the 'piece' strings to the ArrayList.

我有一个字符串,其中有几个单词用空格分隔,例如“firstword second third”和一个ArrayList。我想将字符串拆分成几个部分,并将'piece'字符串添加到ArrayList。

For example,"firstword second third" can be split to three separate strings , so the ArrayList would have 3 elements; "1 2 3 4" can be split into 4 strings, in 4 elements of the ArrayList. See the code below:

例如,“firstword second third”可以拆分为三个单独的字符串,因此ArrayList将有3个元素; “1 2 3 4”可以分成4个字符串,在ArrayList的4个元素中。请参阅以下代码:

public void separateAndAdd(String notseparated) {
    for(int i=0;i<canBeSepartedinto(notseparated);i++{
    //what should i put here in order to split the string via spaces?
        thearray.add(separatedstring);
    }
}

public int canBeSeparatedinto(String string)
    //what do i put here to find out the amount of spaces inside the string? 
    return ....
}

Please leave a comment if you dont get what I mean or I should fix some errors in this post. Thanks for your time!

如果你不理解我的意思,请发表评论或者我应该在这篇文章中修正一些错误。谢谢你的时间!

7 个解决方案

#1


10  

You can split the String at the spaces using split():

您可以使用split()在空格处拆分String:

String[] parts = inputString.split(" ");

Afterwards iterate over the array and add the individual parts (if !"".equals(parts[i]) to the list.

然后迭代数组并将各个部分(如果!“”。equals(parts [i])添加到列表中。

#2


4  

If you want to split on one space, you can use .split(" ");. If you want to split on all spaces in a row, use .split(" +");.

如果要在一个空格上拆分,可以使用.split(“”);.如果要拆分连续的所有空格,请使用.split(“+”);.

Consider the following example:

请考虑以下示例:

class SplitTest {
    public static void main(String...args) {
        String s = "This is a  test"; // note two spaces between 'a' and 'test'
        String[] a = s.split(" ");
        String[] b = s.split(" +");
        System.out.println("a: " + a.length);
        for(int i = 0; i < a.length; i++) {
            System.out.println("i " + a[i]);
        }
        System.out.println("b: " + b.length);
        for(int i = 0; i < b.length; i++) {
            System.out.println("i " + b[i]);
        }
    }
}

If you are worried about non-standard spaces, you can use "\\s+" instead of " +", as "\\s" will capture any white space, not just the 'space character'.

如果您担心非标准空格,可以使用“\\ s +”而不是“+”,因为“\\ s”将捕获任何空白区域,而不仅仅是“空格字符”。

So your separate and add method becomes:

所以你的单独和添加方法变成:

void separateAndAdd(String raw) {
    String[] tokens = raw.split("\\s+");
    theArray.ensureCapacity(theArray.size() + tokens.length); // prevent unnecessary resizes
    for(String s : tokens) {
        theArray.add(s);
    }

}

Here's a more complete example - note that there is a small modification in the separateAndAdd method that I discovered during testing.

这是一个更完整的示例 - 请注意,我在测试期间发现的separateAndAdd方法中有一个小的修改。

import java.util.*;
class SplitTest {
    public static void main(String...args) {
        SplitTest st = new SplitTest();
        st.separateAndAdd("This is a test");
        st.separateAndAdd("of the emergency");
        st.separateAndAdd("");
        st.separateAndAdd("broadcast system.");

        System.out.println(st);
    }

    ArrayList<String> theArray = new ArrayList<String>();

    void separateAndAdd(String raw) {
        String[] tokens = raw.split("\\s+");
        theArray.ensureCapacity(theArray.size() + tokens.length); // prevent unnecessary resizes
        for(String s : tokens) {
            if(!s.isEmpty()) theArray.add(s);
        }
    }

    public String toString() {
        StringBuilder sb = new StringBuilder();
        for(String s : theArray)
            sb.append(s).append(" ");
        return sb.toString().trim();
    }
}

#3


2  

Do this:

thearray = new ArrayList<String>(Arrays.asList(notseparated.split(" ")));

or if thearray already instantiated

或者如果thearray已经实例化了

thearray.addAll(Arrays.asList(notseparated.split(" ")));

#4


2  

I would suggest using the

我建议使用

apache.commons.lang.StringUtils library.

It is the easiest and covers all the different conditions you can want int he spliting up of a string with minimum code.

它是最简单的,涵盖了你可以想要的所有不同条件,用最少的代码分割字符串。

Here is a reference to the split method : Split Method

以下是拆分方法的参考:拆分方法

you can also refer to the other options available for the split method on the same link.

您还可以参考同一链接上可用于拆分方法的其他选项。

#5


1  

You can do that using .split() try this

你可以使用.split()试试这个

String[] words= inputString.split("\\s");

#6


1  

If you want to split the string in different parts, like here i am going to show you that how i can split this string 14-03-2016 in day,month and year.

如果你想在不同的部分拆分字符串,就像在这里我将告诉你如何在日,月和年中分割这个字符串14-03-2016。

 String[] parts = myDate.split("-");
           day=parts[0];
           month=parts[1];
           year=parts[2];

#7


0  

try this: string to 2 part:

试试这个:字符串为2部分:

public String[] get(String s){
    int l = s.length();
    int t = l / 2;
    String first = "";
    String sec = "";
    for(int i =0; i<l; i++){
        if(i < t){
            first += s.charAt(i);
        }else{
            sec += s.charAt(i);
        }
    }
    String[] result = {first, sec};
    return result;
}

example:

String s = "HelloWorld";
String[] res = get(s);
System.out.println(res[0]+" "+res[1])

output:

Hello World

#1


10  

You can split the String at the spaces using split():

您可以使用split()在空格处拆分String:

String[] parts = inputString.split(" ");

Afterwards iterate over the array and add the individual parts (if !"".equals(parts[i]) to the list.

然后迭代数组并将各个部分(如果!“”。equals(parts [i])添加到列表中。

#2


4  

If you want to split on one space, you can use .split(" ");. If you want to split on all spaces in a row, use .split(" +");.

如果要在一个空格上拆分,可以使用.split(“”);.如果要拆分连续的所有空格,请使用.split(“+”);.

Consider the following example:

请考虑以下示例:

class SplitTest {
    public static void main(String...args) {
        String s = "This is a  test"; // note two spaces between 'a' and 'test'
        String[] a = s.split(" ");
        String[] b = s.split(" +");
        System.out.println("a: " + a.length);
        for(int i = 0; i < a.length; i++) {
            System.out.println("i " + a[i]);
        }
        System.out.println("b: " + b.length);
        for(int i = 0; i < b.length; i++) {
            System.out.println("i " + b[i]);
        }
    }
}

If you are worried about non-standard spaces, you can use "\\s+" instead of " +", as "\\s" will capture any white space, not just the 'space character'.

如果您担心非标准空格,可以使用“\\ s +”而不是“+”,因为“\\ s”将捕获任何空白区域,而不仅仅是“空格字符”。

So your separate and add method becomes:

所以你的单独和添加方法变成:

void separateAndAdd(String raw) {
    String[] tokens = raw.split("\\s+");
    theArray.ensureCapacity(theArray.size() + tokens.length); // prevent unnecessary resizes
    for(String s : tokens) {
        theArray.add(s);
    }

}

Here's a more complete example - note that there is a small modification in the separateAndAdd method that I discovered during testing.

这是一个更完整的示例 - 请注意,我在测试期间发现的separateAndAdd方法中有一个小的修改。

import java.util.*;
class SplitTest {
    public static void main(String...args) {
        SplitTest st = new SplitTest();
        st.separateAndAdd("This is a test");
        st.separateAndAdd("of the emergency");
        st.separateAndAdd("");
        st.separateAndAdd("broadcast system.");

        System.out.println(st);
    }

    ArrayList<String> theArray = new ArrayList<String>();

    void separateAndAdd(String raw) {
        String[] tokens = raw.split("\\s+");
        theArray.ensureCapacity(theArray.size() + tokens.length); // prevent unnecessary resizes
        for(String s : tokens) {
            if(!s.isEmpty()) theArray.add(s);
        }
    }

    public String toString() {
        StringBuilder sb = new StringBuilder();
        for(String s : theArray)
            sb.append(s).append(" ");
        return sb.toString().trim();
    }
}

#3


2  

Do this:

thearray = new ArrayList<String>(Arrays.asList(notseparated.split(" ")));

or if thearray already instantiated

或者如果thearray已经实例化了

thearray.addAll(Arrays.asList(notseparated.split(" ")));

#4


2  

I would suggest using the

我建议使用

apache.commons.lang.StringUtils library.

It is the easiest and covers all the different conditions you can want int he spliting up of a string with minimum code.

它是最简单的,涵盖了你可以想要的所有不同条件,用最少的代码分割字符串。

Here is a reference to the split method : Split Method

以下是拆分方法的参考:拆分方法

you can also refer to the other options available for the split method on the same link.

您还可以参考同一链接上可用于拆分方法的其他选项。

#5


1  

You can do that using .split() try this

你可以使用.split()试试这个

String[] words= inputString.split("\\s");

#6


1  

If you want to split the string in different parts, like here i am going to show you that how i can split this string 14-03-2016 in day,month and year.

如果你想在不同的部分拆分字符串,就像在这里我将告诉你如何在日,月和年中分割这个字符串14-03-2016。

 String[] parts = myDate.split("-");
           day=parts[0];
           month=parts[1];
           year=parts[2];

#7


0  

try this: string to 2 part:

试试这个:字符串为2部分:

public String[] get(String s){
    int l = s.length();
    int t = l / 2;
    String first = "";
    String sec = "";
    for(int i =0; i<l; i++){
        if(i < t){
            first += s.charAt(i);
        }else{
            sec += s.charAt(i);
        }
    }
    String[] result = {first, sec};
    return result;
}

example:

String s = "HelloWorld";
String[] res = get(s);
System.out.println(res[0]+" "+res[1])

output:

Hello World