Ios使用字符串中的正则表达式提取数据

时间:2022-09-13 11:24:49

i have

NSString *str =  @"<0x112233><0x112233><0x112233>0a";

i want this data to be saved in nsarray

我希望这些数据保存在nsarray中

nsarray  : { 0x112233 0x112233 0x112233 }

only save data which is enclosed in "<>" and ignore all other.

仅保存包含在“<>”中的数据并忽略所有其他数据。

i tried regex like this

我试过像这样的正则表达式

NSString *str =  @"<0x112233><0x112233><0x112233>0a";

NSError *error2;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"<(.*)>"
                                                                       options:NSRegularExpressionCaseInsensitive
                                                                         error:&error2];
if (error2)
{
    NSLog(@"Error %@", [error2 description]);
}

NSArray *payloadRanges=[regex matchesInString:str options:0 range:NSMakeRange(0, [str length])];


NSLog(@"data %@",payloadRanges);

but i gives me this output:

但我给了我这个输出:

data (
    "<NSSimpleRegularExpressionCheckingResult: 0x1ddc5e30>{0, 30}{<NSRegularExpression: 0x1f078710> <(.*)> 0x1}"
)

4 个解决方案

#1


5  

(As Pat Teen said in a comment), your pattern is greedy, which means that the first match gets as much as possible, which is the entire string.

(正如Pat Teen在评论中所说),你的模式是贪婪的,这意味着第一场比赛尽可能多,这就是整个弦乐。

You can fix that by changing the pattern @"<(.*)>" to @"<(.*?)>".

您可以通过将模式@“<(。*)>”更改为@“<(。*?)>”来解决此问题。

Then payloadRanges is an array of three NSTextCheckingResult objects:

然后payloadRanges是一个包含三个NSTextCheckingResult对象的数组:

(
    "<NSSimpleRegularExpressionCheckingResult: 0x10010af40>{0, 10}{<NSRegularExpression: 0x100108960> <(.*?)> 0x1}",
    "<NSSimpleRegularExpressionCheckingResult: 0x10010c210>{10, 10}{<NSRegularExpression: 0x100108960> <(.*?)> 0x1}",
    "<NSSimpleRegularExpressionCheckingResult: 0x10010c250>{20, 10}{<NSRegularExpression: 0x100108960> <(.*?)> 0x1}"
)

Now you have to extract the substring matching the (...) group from each result:

现在,您必须从每个结果中提取与(...)组匹配的子字符串:

NSMutableArray *data = [NSMutableArray array];
for (NSTextCheckingResult *result in payloadRanges) {
    [data addObject:[str substringWithRange:[result rangeAtIndex:1]]];
}
NSLog(@"data %@",data);

Output:

data (
    0x112233,
    0x112233,
    0x112233
)

#2


1  

Cool , Try this simple line of manually hardcoded without using of any reg exper.:

酷,尝试这个简单的手动硬编码线,而不使用任何reg专业知识:

NSString *convert =[str stringByReplacingOccurrencesOfString:@"<" withString:@""];

    convert= [convert stringByReplacingOccurrencesOfString:@">" withString:@" "];
    NSLog(@"con %@",convert);
    NSMutableArray *array = (NSMutableArray *)[convert componentsSeparatedByString:@" "];
    NSLog(@"%@" ,array);

    for(NSString *str in array){
        if([str length]<4){
            [array removeObject:str];
        }

    }
    NSLog(@"%@",array);

#3


0  

Try this:-

NSString *str =  @"<0x112233><0x112233><0x112233>0a";
NSArray *arr = [str componentsSeparatedByString:@"<"];

    NSString *str1 = [arr lastObject];

    NSArray *arr1 = [str1 componentsSeparatedByString:@">"];

    NSLog(@"array is %@",arr1);

    NSString *str2 = [[arr1 objectAtIndex:0] substringFromIndex:1];

NSString *str3=[str2 stringByReplacingOccurrencesOfString:@"0a" withString:@""];
NSLog(@"str3 is %@",str3);
[yourArray addObject:str3];

#4


0  

Just another regex that should work with your requirements:

只是另一个符合您要求的正则表达式:

<([^>]*)>

#1


5  

(As Pat Teen said in a comment), your pattern is greedy, which means that the first match gets as much as possible, which is the entire string.

(正如Pat Teen在评论中所说),你的模式是贪婪的,这意味着第一场比赛尽可能多,这就是整个弦乐。

You can fix that by changing the pattern @"<(.*)>" to @"<(.*?)>".

您可以通过将模式@“<(。*)>”更改为@“<(。*?)>”来解决此问题。

Then payloadRanges is an array of three NSTextCheckingResult objects:

然后payloadRanges是一个包含三个NSTextCheckingResult对象的数组:

(
    "<NSSimpleRegularExpressionCheckingResult: 0x10010af40>{0, 10}{<NSRegularExpression: 0x100108960> <(.*?)> 0x1}",
    "<NSSimpleRegularExpressionCheckingResult: 0x10010c210>{10, 10}{<NSRegularExpression: 0x100108960> <(.*?)> 0x1}",
    "<NSSimpleRegularExpressionCheckingResult: 0x10010c250>{20, 10}{<NSRegularExpression: 0x100108960> <(.*?)> 0x1}"
)

Now you have to extract the substring matching the (...) group from each result:

现在,您必须从每个结果中提取与(...)组匹配的子字符串:

NSMutableArray *data = [NSMutableArray array];
for (NSTextCheckingResult *result in payloadRanges) {
    [data addObject:[str substringWithRange:[result rangeAtIndex:1]]];
}
NSLog(@"data %@",data);

Output:

data (
    0x112233,
    0x112233,
    0x112233
)

#2


1  

Cool , Try this simple line of manually hardcoded without using of any reg exper.:

酷,尝试这个简单的手动硬编码线,而不使用任何reg专业知识:

NSString *convert =[str stringByReplacingOccurrencesOfString:@"<" withString:@""];

    convert= [convert stringByReplacingOccurrencesOfString:@">" withString:@" "];
    NSLog(@"con %@",convert);
    NSMutableArray *array = (NSMutableArray *)[convert componentsSeparatedByString:@" "];
    NSLog(@"%@" ,array);

    for(NSString *str in array){
        if([str length]<4){
            [array removeObject:str];
        }

    }
    NSLog(@"%@",array);

#3


0  

Try this:-

NSString *str =  @"<0x112233><0x112233><0x112233>0a";
NSArray *arr = [str componentsSeparatedByString:@"<"];

    NSString *str1 = [arr lastObject];

    NSArray *arr1 = [str1 componentsSeparatedByString:@">"];

    NSLog(@"array is %@",arr1);

    NSString *str2 = [[arr1 objectAtIndex:0] substringFromIndex:1];

NSString *str3=[str2 stringByReplacingOccurrencesOfString:@"0a" withString:@""];
NSLog(@"str3 is %@",str3);
[yourArray addObject:str3];

#4


0  

Just another regex that should work with your requirements:

只是另一个符合您要求的正则表达式:

<([^>]*)>