麻烦的
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# TODO 构造增广矩阵，假设A，b行数相同
def augmentMatrix(A, b):
if(len(A) != len(b)):
raise 'The number of rows is different'
result = []
for i in range(len(A)):
row = []
for j in range(len(A[i])):
row.append(A[i][j])
for j in range(len(b[i])):
row.append(b[i][j])
result.append(row)
return result
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优化后
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# TODO 构造增广矩阵，假设A，b行数相同
def augmentMatrix(A, b):
return [AA + bb for AA, bb in zip(A,b)]
A = [[1,2,3],[4,5,6],[7,8,9]]
b = [[1],[2],[3]]
print augmentMatrix(A,b)
[[1, 2, 3, 1], [4, 5, 6, 2], [7, 8, 9, 3]]
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注：解读一下AA+bb, 在 python中, [1, 2, 3] + [4]这样的表达式会返回[1, 2, 3, 4]
以上这篇在Python中构建增广矩阵的实现方法就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/chuan403082010/article/details/79407431