如何在Django名称空间中进行反向URL搜索?

Consider that I include namespaced reusable application:

考虑到我包括了名称空间可重用应用程序:

urlpatterns = patterns('',
    # ella urls
    url('^ella/', include('ella.core.urls', namespace="ella")),
)

Now, the Ella applications has urls like that:

现在，Ella应用程序有这样的url:

urlpatterns = patterns( '',
    url( r'^(?P<category>[a-z0-9-/]+)/$', category_detail, name="category_detail" ),
    # object detail
    url( r'^(?P<category>[a-z0-9-/]+)/(?P<year>\d{4})/(?P<month>\d{1,2})/(?P<day>\d{1,2})/(?P<content_type>[a-z0-9-]+)/(?P<slug>[a-z0-9-]+)/$',
        object_detail, name="object_detail" )
)

Now, calling {% url ella:category_detail category="cat" %} works fine. However, when object tries to generate link to it's details, it calls

现在，调用{% url ella:category_detail类别=“cat”%}工作良好。但是，当对象试图生成链接到它的细节时，它调用。

from django.core.urlresolvers import reverse
url = reverse('object_detail', kwargs={'required' : 'params'})

This is not working, unless rewritten as

这不是工作，除非重写为。

from django.core.urlresolvers import reverse
url = reverse('ella:object_detail', kwargs={'required' : 'params'})

So, if I understand it correctly, including reusable application into namespace breaks all inner reverse()s inside given application.

因此，如果我正确地理解了它，将可重用的应用程序包括到名称空间中，就可以在给定的应用程序中打破所有内部反向()s。

Is it true? What have I missed? Is there any way around?

是真的吗?我错过了什么?有什么办法吗?

3 个解决方案

#1

Since you have name-spaced url configuration, you need to mention namespace:view-name pattern in order to reverse it properly (especially from view).

由于您有名称间隔的url配置，您需要提到名称空间:视图-名称模式，以便正确地反转它(尤其是从视图中)。

But, if you want to avoid this, you may also pass namespace/appname as current_app parameter. There are multiple ways to specify current_app when you are in template. But if you are in view, you need to hard-code as you did, or pass to current_app parameter

但是，如果您想避免这种情况，也可以将命名空间/appname作为current_app参数。在模板中有多种方法来指定current_app。但是如果您在视图中，您需要硬编码，或者传递到current_app参数。

url = reverse('object_detail', 
              kwargs={'foo':'bar'}, 
              current_app=app_name_or_name_space)

refer: http://docs.djangoproject.com/en/dev/topics/http/urls/#reverse

参考:http://docs.djangoproject.com/en/dev/topics/http/urls/逆转

#2

URL Namespaces can be specified in two ways.

可以通过两种方式指定URL名称空间。

Firstly, you can provide the application and instance namespace as arguments to include() when you construct your URL patterns. For example,:

首先，当您构造URL模式时，您可以提供应用程序和实例名称空间作为参数来包含()。例如,:

(r'^help/', include('apps.help.urls', namespace='foo', app_name='bar')),

(r ^ /帮助,包括(“apps.help。url”,名称空间=“foo”,app_name = '酒吧')),

This is right from http://docs.djangoproject.com/en/dev/topics/http/urls/#defining-url-namespaces.

这是来自http://docs.djangoproject.com/en/dev/topics/http/urls/# define -url-namespaces。

Try changing include('ella.core.urls', namespace="ella") to include('ella.core.urls', namespace="ella", app_name="ella"). I'm not 100% this will work, but its worth a shot.

试着改变包括(“ella.core。url”,名称空间=“埃拉”)包括(ella.core。url”,名称空间=“埃拉”,app_name =“埃拉”)。我并不是100%的成功，但值得一试。

#3

At least in Django 1.8 you can write something like this:

至少在Django 1.8中可以这样写:

url = reverse('%s:object_detail' % request.resolver_match.namespace, kwargs={'required' : 'params'})

反向('%s:object_detail' % request.resolver_match.namespace, kwargs={'required': 'params'})

request.resolver_match.namespace is a string containing the namespace of the currently running view.

resolver_match.namespace是一个字符串，包含当前运行视图的名称空间。

#1