如何知道你所构建的iOS应用程序是否为64位。

I am trying to build an iOS Application for 64 bit. How do I know weather it is build for 32 bit or 64 bit ?

我正在尝试构建一个64位的iOS应用程序。我怎么知道它是32位还是64位的?

Does Mach-O-View can help ? if Yes, where to look for it ? Also is there any command line for it. ?

Mach-O-View有用吗?如果是，去哪里找呢?它也有任何命令行。吗?

I reffered this but it does not help me to know weather this it is built or not for 64 bit. https://developer.apple.com/library/ios/documentation/General/Conceptual/CocoaTouch64BitGuide/ConvertingYourAppto64-Bit/ConvertingYourAppto64-Bit.html#//apple_ref/doc/uid/TP40013501-CH3-SW1

我已经回答过这个问题了，但是它并不能帮助我知道它是64位的还是64位的。https://developer.apple.com/library/ios/documentation/General/Conceptual/CocoaTouch64BitGuide/ConvertingYourAppto64-Bit/ConvertingYourAppto64-Bit.html / / apple_ref / doc / uid / TP40013501-CH3-SW1

1 个解决方案

#1

Try this:

试试这个:

#ifdef __LP64__
// NSLog(@"64");
#else
// NSLog(@"32");
#endif

It works for OS X, but I didn't test it for iOS (I don't have an iPhone5S :( ).

它适用于OS X，但我没有对iOS进行测试(我没有iPhone5S:())。

Edit:

编辑:

By the way, it works fine on iPhone Simulator.

顺便说一下，它在iPhone模拟器上运行良好。