命题:从成员数为N的集合S中,选出M个元素,分别求其排列与组合结果集,即 A(N, M)与C(N, M)
js解法:
function queue(arr, size){
if(size > arr.length){ return;}
var allResult = []; (function(arr, size, result){
if(result.length == size){
allResult.push(result);
}else{
for(var i =0 ,len = arr.length;i < len; i++){
var newArr = [].concat(arr),
curItem = newArr.splice(i,1);
arguments.callee(newArr, size, [].concat(result,curItem));
}
}
})(arr, size, []); return allResult;
} function choose(arr, size ){
var allResult = []; (function(arr, size, result){
var arrLen = arr.length;
if(size > arrLen){
return;
}
if(size == arrLen){
allResult.push([].concat(result, arr))
}else{
for(var i =0 ; i < arrLen; i++){
var newResult = [].concat(result);
newResult.push(arr[i]); if(size == 1){
allResult.push(newResult);
}else{
var newArr = [].concat(arr);
newArr.splice(0, i + 1);
arguments.callee(newArr, size - 1, newResult);
}
}
}
})(arr, size, []); return allResult;
} function showResult(result){
console.log('The number of result sets: ' + result.length );
for(var i=0 , len = result.length;i < len; i++){
console.log(result[i]);
}
} var arr = ['姬光','王子', '三桂','科长']; showResult(choose(arr, 4));
showResult(queue(arr, 4));
个人原创,如有漏洞或建议,请留言。