判断一棵树是否是另一棵树的子树

问题

判断一棵树是否是另一棵树的子树，如图

思路

问题分两步：

• 找值相同的根结点（遍历解决）
• 判断两结点是否包含（递归：值、左孩子、右孩子分别相同）

树节点定义

struct TreeNode
{
int val;
    TreeNode *next;
    TreeNode(int v) : val(v), next(NULL) {}
};

代码

bool IsPart(TreeNode *root1, TreeNode *root2)
{
if (root2 == NULL)
return true;
if (root1 == NULL)
return false;
if (root1->val != root2->val)
return false;
return IsPart(root1->left, root2->left) &&
        IsPart(root1->right, root2->right);
}
bool IsPartTree(TreeNode *root1, TreeNode *root2)
{
bool result = false;
if (root1 != NULL && root2 != NULL)
    {
if (root1->val == root2->val)
            result = IsPart(root1, root2);
if (!result)
            result = IsPartTree(root1->left, root2);
if (!result)
            result = IsPartTree(root1->right, root2);
    }
return result;
}

执行

#include <iostream>
#include <stack>
using namespace std;
struct TreeNode
{
int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode(int v) : val(v), left(NULL), right(NULL) {}
};
bool IsPart(TreeNode *root1, TreeNode *root2)
{
if (root2 == NULL)
return true;
if (root1 == NULL)
return false;
if (root1->val != root2->val)
return false;
return IsPart(root1->left, root2->left) &&
        IsPart(root1->right, root2->right);
}
bool IsPartTree(TreeNode *root1, TreeNode *root2)
{
bool result = false;
if (root1 != NULL && root2 != NULL)
    {
if (root1->val == root2->val)
            result = IsPart(root1, root2);
if (!result)
            result = IsPartTree(root1->left, root2);
if (!result)
            result = IsPartTree(root1->right, root2);
    }
return result;
}
TreeNode* createTree1()
{
    TreeNode *root = new TreeNode(1);
    TreeNode *p1 = new TreeNode(2);
    TreeNode *p2 = new TreeNode(3);
    TreeNode *p3 = new TreeNode(4);
    TreeNode *p4 = new TreeNode(5);
    root->left = p1;
    root->right = p2;
    p2->left = p3;
    p2->right = p4;
return root;
}
TreeNode* createTree2()
{
    TreeNode *root = new TreeNode(1);
    TreeNode *p1 = new TreeNode(2);
    TreeNode *p2 = new TreeNode(3);
    root->left = p1;
    root->right = p2;
return root;
}


void deleteTree(TreeNode *root)
{
if (root != NULL)
    {
        delete(root->left);
        delete(root->right);
        delete root;
        root = NULL;
    }
}
int main()
{
    TreeNode *root1 = createTree1();
    TreeNode *root2 = createTree2();
    cout << IsPartTree(root1, root2) << endl;
    deleteTree(root1);
    deleteTree(root2);
}

 

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