So I have the following piece of code:
所以我有以下的一段代码:
var structures = {
loginStructure : function(){
return structure = [
'<form name="',opts.formClass,'" class="',opts.formClass,'" method="post" action="#">',
'<fieldset class="',opts.fieldsWrapper,'">',
'<fieldset class="',opts.userWrapper,'">',
'<label for="',opts.userInt,'" class="',opts.userLbl,'"><img src="',opts.userIcon,'" alt="',opts.userName,'" /></label>',
'<input type="text" name="',opts.userInt,'" class="',opts.userInt,'" placeholder="',checkNameLenght(opts.userName,namesLenght.userNameLenght,16,'Username'),'" value="" autocomplete="off" />',
'</fieldset>',
'<fieldset class="',opts.passWrapper,'">',
'<label for="',opts.passInt,'" class="',opts.passLbl,'"><img src="',opts.passIcon,'" alt="',opts.passName,'" /></label>',
'<input type="password" name="',opts.passInt,'" class="',opts.passInt,'" placeholder="',checkNameLenght(opts.passName,namesLenght.passNameLenght,16,'Password'),'" value="" autocomplete="off" />',
'</fieldset>',
'<fieldset class="',opts.btnWrapper,'">',
'<button type="submit" name="',opts.btnInt,'" class="',opts.btnInt,'">',checkNameLenght(opts.btnName,namesLenght.btnNameLenght,7,'Login'),'</button>',
'</fieldset>',
'</fieldset>',
'<div class="toogle-button">',
'<ul class="inside">',
'<li class="toogle"><a><img src="assets/gfx/toogle.png" alt="Back" /></a></li>',
'</ul>',
'</div>',
'</form>',
'<div class="toogle-buttons">',
'</div>'
];
}
}
This returns ( if I do console.log(structures.loginStructure) ) just a function(). Is there a way I can make it to return the actual array I have in there ?
这个返回(如果我做了console.log(structures.loginStructure))只是一个函数()。有没有一种方法可以让它返回我在那里的实际数组?
The purpose of it would be to have multiple arrays defined as object keys, if it is possible to return such a thing, because it seems easier. Or is there a better way to do this ?
如果可能的话，它的目的是将多个数组定义为对象键，因为它看起来更简单。或者有更好的方法吗?
1 个解决方案
#1
4
You want:
你想要的:
structures.loginStructure();
structures.loginStructure is simply just returning a reference to the function, instead of executing the function and returning its result. Add the () to the end of it to execute it and return its result.
结构。loginStructure只是返回对函数的引用，而不是执行函数并返回结果。将()添加到末尾以执行它并返回结果。
Alternatively, and maybe better, don't write it as a function. Just declare loginStructure: ['<form name.... Basically, just remove function(){return structure =. A significant difference to note here is that any values of opts would be evaluated immediately, instead of deferred until later when then function would be executed - so please don't blindly update your code to this.
或者，也许更好，不要把它写成函数。刚刚宣布loginStructure:[' <表单名称....基本上，只需删除function(){return structure="。这里需要注意的一个重要的区别是，任何opts的值都将立即被评估，而不是延迟到稍后才会执行，所以请不要盲目地更新你的代码。
#1
4
You want:
你想要的:
structures.loginStructure();
structures.loginStructure is simply just returning a reference to the function, instead of executing the function and returning its result. Add the () to the end of it to execute it and return its result.
结构。loginStructure只是返回对函数的引用，而不是执行函数并返回结果。将()添加到末尾以执行它并返回结果。
Alternatively, and maybe better, don't write it as a function. Just declare loginStructure: ['<form name.... Basically, just remove function(){return structure =. A significant difference to note here is that any values of opts would be evaluated immediately, instead of deferred until later when then function would be executed - so please don't blindly update your code to this.
或者，也许更好，不要把它写成函数。刚刚宣布loginStructure:[' <表单名称....基本上，只需删除function(){return structure="。这里需要注意的一个重要的区别是，任何opts的值都将立即被评估，而不是延迟到稍后才会执行，所以请不要盲目地更新你的代码。