I have two MySQL tables (product and price history) that I would like to join:
我有两个MySQL表(产品和价格历史),我想加入:
Product
table:
产品表:
Id = int
Name = varchar
Manufacturer = varchar
UPC = varchar
Date_added = datetime
Price_h
table:
Price_h表:
Id = int
Product_id = int
Price = int
Date = datetime
I can perform a simple LEFT JOIN:
我可以执行一个简单的左连接:
SELECT Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM Product
LEFT JOIN Price_h
ON Product.Id = Price_h.Product_id;
But as expected if I have more than one entry for a product in the price history table, I get one result for each historical price.
但正如预期的那样,如果在价格历史表中有一个以上的产品条目,那么每个历史价格将得到一个结果。
How can a structure a join that will only return one instance of each produce with only the newest entry from the price history table joined to it?
如何构造一个连接,它只返回每个产品的一个实例,而只返回与它连接的价格表中最新的条目?
5 个解决方案
#1
22
Use:
使用:
SELECT p.upc,
p.name,
ph.price,
ph.date
FROM PRODUCT p
LEFT JOIN PRICE_H ph ON ph.product_id = p.id
JOIN (SELECT a.product_id,
MAX(a.date) AS max_date
FROM PRICE_H a
GROUP BY a.product_id) x ON x.product_id = ph.product_id
AND x.max_date = ph.date
#2
3
Try this:
试试这个:
SELECT Product.UPC, Product.Name, Price_h.Price, MAX(Price_h.Date)
FROM Product
INNER JOIN Price_h
ON Product.Id = Price_h.Product_id
GROUP BY Product.UPC, Product.Name, Price_h.Price
#3
3
SELECT Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM Product
LEFT JOIN Price_h
ON (Product.Id = Price_h.Product_id AND Price_h.Date =
(SELECT MAX(Date) FROM Price_h ph1 WHERE ph1.Product_id = Product.Id));
#4
0
SELECT n.product_id,
n.product_name,
n.product_articul,
n.product_price,
n.product_discount,
n.product_description,
n.product_care,
(SELECT photo_name FROM siamm_product_photos WHERE product_id = n.product_id LIMIT 1) AS photo_name
FROM siamm_product as n;
#5
0
Why not keep it simple and fast:
为什么不保持简单和快速:
SELECT
Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM
Product
LEFT JOIN
Price_h
ON Product.Id = Price_h.Product_id;
ORDER BY
Price_h.Date DESC
LIMIT 1
#1
22
Use:
使用:
SELECT p.upc,
p.name,
ph.price,
ph.date
FROM PRODUCT p
LEFT JOIN PRICE_H ph ON ph.product_id = p.id
JOIN (SELECT a.product_id,
MAX(a.date) AS max_date
FROM PRICE_H a
GROUP BY a.product_id) x ON x.product_id = ph.product_id
AND x.max_date = ph.date
#2
3
Try this:
试试这个:
SELECT Product.UPC, Product.Name, Price_h.Price, MAX(Price_h.Date)
FROM Product
INNER JOIN Price_h
ON Product.Id = Price_h.Product_id
GROUP BY Product.UPC, Product.Name, Price_h.Price
#3
3
SELECT Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM Product
LEFT JOIN Price_h
ON (Product.Id = Price_h.Product_id AND Price_h.Date =
(SELECT MAX(Date) FROM Price_h ph1 WHERE ph1.Product_id = Product.Id));
#4
0
SELECT n.product_id,
n.product_name,
n.product_articul,
n.product_price,
n.product_discount,
n.product_description,
n.product_care,
(SELECT photo_name FROM siamm_product_photos WHERE product_id = n.product_id LIMIT 1) AS photo_name
FROM siamm_product as n;
#5
0
Why not keep it simple and fast:
为什么不保持简单和快速:
SELECT
Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM
Product
LEFT JOIN
Price_h
ON Product.Id = Price_h.Product_id;
ORDER BY
Price_h.Date DESC
LIMIT 1