如何在jQuery / Ajax成功方法之后调用另一个php页面？

I have following Ajax Success method :

我有以下Ajax Success方法：

 success: function(data, el){

    var parent = el.find(".jFiler-jProgressBar").parent();

    el.find(".jFiler-jProgressBar").fadeOut("slow", function(){
    $("<div class=\"jFiler-item-others text-success\"><i class=\"icon-jfi-check-circle\"></i> Success <b class=\"text-danger\">&nbsp;&nbsp;&nbsp;<a href=\"#delete_upload_image\">Delete</a></b></div>").hide().appendTo(parent).fadeIn("slow");    
    });

    console.log(data);        
 },

In this success method you see that I have a link which is :

在这个成功方法中，您会看到我有一个链接：

<a href=\"#delete_upload_image\">Delete</a>

and

和

console.log(data)

This console.log(data) is returning following String :

此console.log（数据）返回以下字符串：

mpic_list_573ecaafae8220.41741946 |76|40

Now I want call a php page e.g : delete_upload_image.php after click on this link <a href=\"#delete_upload_image\">Delete</a> with a string mpic_list_573ecaafae8220.41741946 and 76 and 40

现在我想调用一个php页面，例如：delete_upload_image.php点击此链接删除后，用字符串mpic_list_573ecaafae8220.41741946和76和40

I mean :

我的意思是：

In delete_upload_image.php page I can get 3 string which is passed when I click on the delete link. `

在delete_upload_image.php页面中，我可以获得3个字符串，当我点击删除链接时会传递该字符串。 `

4 个解决方案

#1

You must either bind the click to a function where you send the user to the desired page or directly make a link in the button.

您必须将单击绑定到将用户发送到所需页面的功能，或者直接在按钮中创建链接。

First, if you want to send the differents params separately, you must split them.

首先，如果要单独发送不同的参数，则必须将它们拆分。

var params = data.split('|');

And then use it as you want, for example bind the click method to the new link to create a new ajax call.

然后根据需要使用它，例如将click方法绑定到新链接以创建新的ajax调用。

$('#delete_upload_image').on('click', function() {
    var params = data.split('|');
    var url = "delete_upload_image.php?param1=" + params[0] +"&param2=" + params[1] + "&param3=" + params[2];

    // Make AJAX call as you want to url
    $.get(url);

});

#2

Catch your parameters in your data using split method :

使用拆分方法在数据中捕获参数：

var stringParam = data.split('|')[0];
var int1Param= data.split('|')[1];
var int2Param= data.split('|')[2];

then put your parameters inside your link :

然后将您的参数放在链接中：

$("<div class=\"jFiler-item-others text-success\"><i class=\"icon-jfi-check-circle\"></i> Success <b class=\"text-danger\">&nbsp;&nbsp;&nbsp;<a href=\"delete_upload_image.php?string="+ stringParam +"&int=" + int1Param + "&secondint=" + int2Param + "\">Delete</a></b></div>").hide().appendTo(parent).fadeIn("slow");

#3

you must put your data in your link tag:
您必须将数据放入链接标记中：

<a href=\"#delete_upload_image\" data-params='" + data + "'>Delete</a>

then you can send delete requests to "delete_upload_image.php" by below codes:
然后你可以通过以下代码发送删除请求到“delete_upload_image.php”：

$(function(){
  $('body').on('click', '[href=#delete_upload_image]', function() {
    var params = $(this).data('params').split('|');
    var url = "delete_upload_image.php?param1=" + params[0] +"&param2=" + params[1] + "&param3=" + params[2];

    // Make AJAX call as you want to url
    $.get(url);
  });      
});

#4

now I understand what is your problem;

现在我明白你的问题是什么;

You want to get the parameters from console.log.

您想从console.log获取参数。

but you can not get the console.log value directly.

但是你无法直接获得console.log值。

What you can do is:

你能做的是：

hook the console.log function so that you store when it logs by this code:
挂钩console.log函数，以便在通过此代码记录时进行存储：

var store = '';
var oldf = console.log;
console.log = function(){
   store = JSON.stringify(arguments);
   oldf.apply(console, arguments);
}

use below function to get parameters from console_store variable and delete image:
使用下面的函数从console_store变量获取参数并删除图像：

function delete_image()
{
  var params = store.split('|'),
  queryString = $.param({param0:params[0], param1:params[1], param2:params[2]}),
  url = "delete_upload_image.php?" + queryString;
  $.get(url);
}

call the function on link click:
在链接点击上调用该功能：

$('body').on('click', '[href=#delete_upload_image]', delete_image);

#1