利用ajax提交表单,实现数据前端后台数据交互的完整流程演示

时间:2022-01-31 19:22:05

该演示需要用到  1 : json.jar(下载)

                              2 : jquery.js(下载)

流程演示:1.点击“登录”按钮,传参到后台

                    2.后台获取数据,处理分析数据,利用JSONObject返回结果(JSONObject需要用到一个 json.jar 即可)

                   3.前端获取后台返回的结果进行判断,然后前端分析该结果,再决定进入后台的最后一个环节(登录是否成功的跳转)

                   4.页面跳转


效果演示:

登录页面:

利用ajax提交表单,实现数据前端后台数据交互的完整流程演示


用户名密码都正确,跳转到index

利用ajax提交表单,实现数据前端后台数据交互的完整流程演示


工程目录树:

利用ajax提交表单,实现数据前端后台数据交互的完整流程演示



具体流程:

1,在WebContent目录下新建一个toLogin.jsp , 用于跳转到login.jsp页面

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<jsp:forward page="login.do?method=0"></jsp:forward>

2.Servlet:

@WebServlet("/login.do")  //servlet的名字
public class login extends HttpServlet {


private static final long serialVersionUID = 4306651429943204510L;

public final static String To_login_Page = "0";
public final static String login = "1";
public final static String index = "2";

@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {

doPost(req, resp);
}

@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {

String method = req.getParameter("method");
switch(method){
case To_login_Page:
To_login_Page(req,resp);
break;
case login:
login(req,resp);
break;
case index:
index(req,resp);
break;
}
}

private void index(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
req.getRequestDispatcher("WEB-INF/view/index.jsp").forward(req, resp);

}

private void To_login_Page(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
req.getRequestDispatcher("WEB-INF/view/login.jsp").forward(req, resp);
}

private void login(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
String username = req.getParameter("username");
String password = req.getParameter("password");
System.out.println(username);
System.out.println(password);
boolean IsOK = false;
if(username.equals("admin")&&password.equals("123456")){
IsOK = true;
}else{
IsOK = false;
}
try {
JSONObject json = new JSONObject();
json.put("IsOK", IsOK);
PrintWriter out = resp.getWriter();
out.println(json.toString());
out.close();
} catch (JSONException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}

3.login.jsp:

<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>login</title>
<script type="text/javascript" src="${pageContext.request.contextPath}/js/jquery-2.1.4.min.js"></script>
</head>
<body>
<form id="form" action="" method="post">
<input type="text" id="username"> <br>
<input type="password" id="password"> <br>
<input type="button" id="btn" value="登录">
</form>

<script>
$(document).ready(function(){
$("#btn").click(function(){
var name = $("#username").val();
var pwd = $("#password").val()
$.post("login.do?method=1", //利用ajax发起请求,这里写servlet的路径
{"username":name,"password":pwd}, //传参
function(data){ //请求成功时的回调函数
if(data.IsOK == true){
window.location.href="login.do?method=2"; //如果返回的IsOK的值为true,也就是用户名密码都正确,则执行该跳转
}else{
window.location.href="http://www.baidu.com";
}
},
"json"
);
})
})
</script>
</body>
</html>


如果实在看不懂,可以尝试下载我的project,去运行,需要说明的是,我建立该工程的环境是tomcat 9

下载地址:http://download.csdn.net/detail/a13432421434/9819642

当然,用ajax提交表单比一般的表单提交代码量多那么一点,至于两种方式提交的区别,还是这里比较有说服力:http://www.cnblogs.com/zhujiabin/p/4901167.html