如何在Mongoose模型中存根方法？

How to stub the instance method bark of the following fictitious schema?

如何存根以下虚构架构的实例方法?

var dogSchema = mongoose.Schema({
  // ...
});

dogSchema.methods = {
  bark() { console.log('Woof!') },
};

For example, if I want to test the following function barkOne():

例如,如果我想测试以下函数barkOne():

function barkOne() {
  Dog.findOne().exec().then(dog => dog.bark());
}

How would I be able to stub it, in order to test it like this?

我怎么能将它存根,以便像这样测试它?

describe('barkOne', () =>
  it('should make all dogs bark', () => {
    barkOne().then(() => {
      assert(barkStub.calledOnce);
    });
  })
});

Thanks!

1 个解决方案

#1

As of mongoose 4.4.5, I was able to stub methods with Model.prototype. e.g.

从mongoose 4.4.5开始,我能够使用Model.prototype来存根方法。例如

const stub = sandbox.stub(Dog.prototype, 'bark');

Dog.findOne().exec().then(dog => {
  // dog[0].bark === stub
})