在数组中获得数字元素或在变量上使用时仅返回1的通用宏?

In C language macro for getting number of array elements is well known and looks like this:

在C语言中，获取数组元素的数量是众所周知的，如下所示:

uint32_t buffer[10];

#define ARRAY_SIZE(x)     sizeof(x)/sizeof(x[0])

size_t size = ARRAY_SIZE(buffer);

The question is, is there any universal macro for getting array elements or returning just one when it's used on variable ? I mean following usage of macro :

问题是，是否有一个通用的宏来获取数组元素，或者在变量使用时只返回一个?我的意思是在使用宏的时候

uint32_t buffer[10];
uint32_t variable;

#define GET_ELEMENTS(x)     ???

size_t elements_of_array = GET_ELEMENTS(buffer); // returns 10
size_t elements_of_variable = GET_ELEMENTS(variable); // returns 1

Does anybody know the solution ?

有人知道答案吗?

I've edited my question because it was wrongly formulated, BTW I know that I can use :

我已经编辑了我的问题，因为它被错误地表述了，我知道我可以使用:

sizeof(variable)/sizeof(uint32_t)

Question is how to combine it in one macro or maybe inline function is better solution ?

问题是如何在一个宏或内联函数中组合它是更好的解决方案?

1 个解决方案

#1

You could use sizeof, like this:

你可以使用sizeof，像这样:

#include <stdio.h>

int main(void)
{
  unsigned int buffer[10];
  // size of one unsigned int
  printf("%zu\n", sizeof(unsigned int));

  // this will print the number of elements of buffer * size of an unsigned int
  printf("%zu\n", sizeof(buffer));

  // you have a mistake
  // the following printf() gives you the number of elements
  printf("%d\n", sizeof(buffer)/sizeof(buffer[0]));
  return 0;
}

Output (on my machine):

输出(在我的机器上):

4
40
10

Regarding the edit you made:

关于你的编辑:

You can't perform type checking in C, thus you can not check if what you pass is an array or a variable.

您不能在C中执行类型检查，因此您不能检查您传递的是一个数组还是一个变量。

#1