I have .ogg files in res/raw, I have implemented a feature to save file to sdcard, and I want to set file name from original file.
我在res/raw文件中有.ogg文件，我实现了将文件保存到sdcard的功能，我想从原始文件中设置文件名。
3 个解决方案
#2
8
Use Resources.getResourceName(id) to get package:type/entryname, or Resources.getResourceEntryName(id) to get entry name (file name.)
使用Resources.getResourceName(id)获取包:type/entryname，或Resources.getResourceEntryName(id)以获取条目名称(文件名)。
#3
1
If you're looking for the name from a resource ID, you can use Resources.getResourceName(). You can get the Resources object using Context.getResources().
如果要从资源ID中查找名称，可以使用Resources.getResourceName()。您可以使用Context.getResources()获取资源对象。
Personally, I'd rather store an array of strings in your strings.xml and map that to the resource IDs, but it depends on what you're really trying to accomplish.
就我个人而言，我宁愿将字符串数组存储在字符串中。xml并将其映射到资源id，但这取决于您真正想要实现的目标。
#1
#2
8
Use Resources.getResourceName(id) to get package:type/entryname, or Resources.getResourceEntryName(id) to get entry name (file name.)
使用Resources.getResourceName(id)获取包:type/entryname，或Resources.getResourceEntryName(id)以获取条目名称(文件名)。
#3
1
If you're looking for the name from a resource ID, you can use Resources.getResourceName(). You can get the Resources object using Context.getResources().
如果要从资源ID中查找名称，可以使用Resources.getResourceName()。您可以使用Context.getResources()获取资源对象。
Personally, I'd rather store an array of strings in your strings.xml and map that to the resource IDs, but it depends on what you're really trying to accomplish.
就我个人而言，我宁愿将字符串数组存储在字符串中。xml并将其映射到资源id，但这取决于您真正想要实现的目标。