Angular-ui bootstrap模式，无需创建新控制器

plunk: http://plnkr.co/edit/85Wl5W If I use the $modalInstance on the same controller(modalController.js), without being in a modal, angular gets frozen.

plunk：http：//plnkr.co/edit/85Wl5W如果我在同一个控制器上使用$ modalInstance（modalController.js），而不是在模态中，则角度会被冻结。

I just want to simplify my life using angularjs with the angular-ui bootstrap modal service. I want to use the same controller on a separate file, but on a modal as well. That is, I want them to do the same task. Is there any proper way to do it?

我只想用angular-ui bootstrap模态服务使用angularjs来简化我的生活。我想在一个单独的文件上使用相同的控制器，但也在一个模态上。也就是说，我希望他们做同样的任务。有没有正确的方法呢？

E.g. modal.html, modalController.js. I want to show these on a modal window, but on my application as well without a modal. The issue is that if I use the same controller I can't inject the $modalInstance, as it's undefined if there's no modal.

例如。 modal.html，modalController.js。我想在模态窗口上显示这些，但在我的应用程序中也没有模态。问题是，如果我使用相同的控制器，我无法注入$ modalInstance，因为如果没有模态，它是未定义的。

Thanks in advance,

提前致谢，

Alex

亚历克斯

3 个解决方案

#1

It was possible in older version of UI-Bootstrap 0.10.0 .Even latest version,it works for me

有可能在旧版本的UI-Bootstrap 0.10.0。即使是最新版本，它也适用于我

index.html

<!-- if you are using Bower -->    
<script src="bower_components/angular-bootstrap/ui-bootstrap.min.js">
</script>
<script src="bower_components/angular-bootstrap/ui-bootstrap-tpls.min.js">
</script>

<!-- modal -->
<!-- look at 'type' and 'id' values -->
<script type="text/ng-template" id="myTestModal.tmpl.html">
    <div class="modal-header">
        <h3>Modal Header</h3>
    </div>   

    <div class="modal-body">
        <p>Modal Body</p>
    </div>

    <div class="modal-footer">
        <button type="button" class="btn btn-default" ng-click="close()" data-dismiss="modal">Close
        </button>
        <button type="button" class="btn btn-primary" ng-click="doSomething()">Do Something
        </button>
    </div> 
</script>

modalDemoController.js

$scope.openModal=function(){
    $scope.modalInstance=$modal.open({
        templateUrl: 'myTestModal.tmpl.html',
        scope:$scope
    });
}

$scope.close=function(){
    $scope.modalInstance.dismiss();//$scope.modalInstance.close() also works I think
};

$scope.doSomething=function(){
    //any actions to take place
    console.log("Do Something");
}

#2

I haven't found a clean solution yet, the best workaround I found, to avoid writing the same code twice was to extend the modal controller like this:

我还没有找到一个干净的解决方案，我找到的最好的解决方法，避免两次编写相同的代码是扩展模态控制器，如下所示：

$.extend(this, $controller('NormalCtrl', {$scope: $scope}));

full controller:

完全控制器：

.controller('ModalCtrl', ['$scope', '$controller', '$modalInstance', 
function ($scope, $controller, $modalInstance) {
    //with this line here:
    // Initialize the super class and extend it.
    $.extend(this, $controller('NormalCtrl', {$scope: $scope}));

    // Opens a search result
    $scope.openResult = function() {
        $modalInstance.close($scope.selectedRow);
    };

    // Called when the cancel button is pressed
    $scope.back = function() {
        $modalInstance.dismiss('cancel');
    };

}]);

That way, I can re-use the same code, without having to rewrite it all over again and I can override the functions that I want to do smth different to the original controller.

这样，我可以重复使用相同的代码，而不必重新编写它，我可以覆盖我想要做的与原始控制器不同的函数。

Hope I helped some people out there,

希望我能帮助一些人，

Alex

亚历克斯

#3

Just write a function instead of creating new file:

只需编写一个函数而不是创建新文件：

 $scope.yourModal= function (data) {
   var modalInstance = $modal.open({
     template: '<div>Do you really want to hurt me? <div><button class="btn" ng-click="hurt(data)">Yes</button></div></div>',
     controller: function($scope, scope){
        $scope = scope;
     },
     resolve: {
         scope: function () {
            return $scope;
         }
     },
     size: 'sm'
   });  
 }

 $scope.hurt = function(data){
     console.log(data);
 }