分享一个linux系统中循环遍历两个数组内容,并输出数组中的不同内容的shell脚本

时间:2022-11-17 18:37:08

cat diffarray.sh

#!/bin/bash
arry_list1=(1 2 3 4 5 6 7 8 9)
arry_list2=(3 5 8) declare -a diff_list
t=0
flag=0
echo arry_list1=${arry_list1[@]}
echo arry_list2=${arry_list2[@]} for list1_num in "${arry_list1[@]}"
do
echo list1_num is ${list1_num}
for list2_num in "${arry_list2[@]}"
do
echo list2_num is ${list2_num}
if [[ "${list1_num}" == "${list2_num}" ]]; then
flag=1
break
fi
done
if [[ $flag -eq 0 ]]; then
diff_list[t]=$list1_num
t=$((t+1))
else
flag=0
fi
done
echo diff_list=${diff_list[@]}