I have an array @genotypes = "TT AG TT AG...." and want to add a spike to it (e.g. 20 x TT) to make a new array.
我有一个数组@genotypes =“TT AG TT AG ....”并希望添加一个尖峰（例如20 x TT）来制作一个新阵列。
I can obviously push "TT" into the array 20 times - but is there a simpler way of doing this? (ie. not @newarray = push @genotypes ("TT", "TT", "TT",......20 times!);
我显然可以将“TT”推入阵列20次 - 但有没有更简单的方法呢？ （即不是@newarray =推@genotypes（“TT”，“TT”，“TT”，...... 20次！）;
3 个解决方案
#1
35
@newlist = (@genotypes, ('TT') x 20);
Yes, it is an x.
是的，它是一个x。
See Multiplicative Operators in perldoc perlop.
请参阅perldoc perlop中的乘法运算符。
#2
4
The repetition operator is the most obvious way.
You could also use map:
重复算子是最明显的方式。你也可以使用map：
@newarray = (@genotypes, map 'TT', 1..20);
#3
3
There's also the foreach way of pushing multiple identical values to an array:
还有将多个相同值推送到数组的foreach方法：
push @newarray, 'TT' foreach (1..20);
#1
35
@newlist = (@genotypes, ('TT') x 20);
Yes, it is an x.
是的，它是一个x。
See Multiplicative Operators in perldoc perlop.
请参阅perldoc perlop中的乘法运算符。
#2
4
The repetition operator is the most obvious way.
You could also use map:
重复算子是最明显的方式。你也可以使用map：
@newarray = (@genotypes, map 'TT', 1..20);
#3
3
There's also the foreach way of pushing multiple identical values to an array:
还有将多个相同值推送到数组的foreach方法：
push @newarray, 'TT' foreach (1..20);