解法1:SPFA算法找负环和求最短路径 设超级源点
#include<bits/stdc++.h>
using namespace std;
#define N 1005
#define INF 0x3f3f3f3f3f3f3f3f
struct Edge
{
int v, w;
};
long long n, m, s, dis[N], enqueNum[N];
vector<Edge> edge[N];
bool inQue[N];
bool spfa(int sv)
{
memset(dis, 0x3f, sizeof(dis));
queue<int> que;
dis[sv] = 0;
que.push(sv);
inQue[sv] = true;
enqueNum[sv]++;
while(!que.empty())
{
int u = que.front();
que.pop();
inQue[u] = false;
for(Edge e : edge[u])
{
int v = e.v, w = e.w;
if(dis[v] > dis[u]+w)
{
dis[v] = dis[u]+w;
if(!inQue[v])
{
if(++enqueNum[v] > n)
return true;
que.push(v);
inQue[v] = true;
}
}
}
}
return false;
}
int main()
{
int u, v, w;
cin >> n >> m >> s;
for(int i = 1; i <= m; ++i)
{
cin >> u >> v >> w;
edge[u].push_back(Edge{v, w});
}
for(int i = 1; i <= n; ++i)
edge[0].push_back(Edge{i, 0});
bool hasNegRing = spfa(0);
if(hasNegRing)
cout << -1;
else
{
spfa(s);
for(int i = 1; i <= n; ++i)
{
if(dis[i] == INF)
cout << "NoPath" << '\n';
else
cout << dis[i] << '\n';
}
}
return 0;
}
解法2:尝试从每个顶点出发调用SPFA_DFS算法找负环,SPFA求最短路径
#include <bits/stdc++.h>
using namespace std;
#define N 1005
#define INF 0x3f3f3f3f3f3f3f3f
struct Edge
{
int v, w;
};
int n, m, s;
long long dis[N];
vector<Edge> edge[N];
bool inStk[N], inQue[N], hasNegRing;
void spfa_dfs(int u)
{
if(hasNegRing)
return;
inStk[u] = true;
for(Edge e : edge[u])
{
int v = e.v, w = e.w;
if(dis[v] > dis[u]+w)
{
dis[v] = dis[u]+w;
if(inStk[v])
{
hasNegRing = true;
return;
}
spfa_dfs(v);
}
}
inStk[u] = false;
}
void spfa_bfs(int u)
{
memset(dis, 0x3f, sizeof(dis));
queue<int> que;
inQue[u] = true;
dis[u] = 0;
que.push(u);
while(!que.empty())
{
int u = que.front();
que.pop();
inQue[u] = false;
for(Edge e : edge[u])
{
int v = e.v, w = e.w;
if(dis[v] > dis[u]+w)
{
dis[v] = dis[u]+w;
if(!inQue[v])
{
inQue[v] = true;
que.push(v);
}
}
}
}
}
int main()
{
int f, t, w;
cin >> n >> m >> s;
for(int i = 1; i <= m; ++i)
{
cin >> f >> t >> w;
edge[f].push_back(Edge{t, w});
}
for(int v = 1; v <= n; ++v)
{
spfa_dfs(v);
if(hasNegRing)
{
cout << -1;
return 0;
}
}
spfa_bfs(s);
for(int i = 1; i <= n; ++i)
{
if(dis[i] == INF)
cout << "NoPath" << endl;
else
cout << dis[i] << endl;
}
return 0;
}