使用tumblr API获取前五个帖子

$feedURL = 'http://########.tumblr.com/api/read/';
$xml = simplexml_load_file($feedURL);

foreach($xml->posts->post as $post){
   $posts = (string) $post->{'photo-caption'}; 
   $img = (string) $post->{'photo-url'};
   echo "<div style='width:518px;height:300px;'><div style='width:200px;height:200px;float:left;'>".'<img style="width:200px;height:200px;" src="' . $img . '" />'."</div><div style='width:300px;float:right;'>".$posts."</div></div><br>";
}

I have used this code to display all the available posts, but i want to display just first five posts

我已经使用此代码显示所有可用的帖子,但我想只显示前五个帖子

2 个解决方案

#1

According to the tumblr API, you can append a querystring parameter num to limit the number of posts returned from the API call. I have no personal experience with the Tumblr API, but you might try something like this to limit the number of posts read:

根据tumblr API,您可以附加查询字符串参数num以限制从API调用返回的帖子数。我没有使用Tumblr API的个人经验,但您可以尝试这样的方法来限制读取的帖子数量:

$numPosts = 5;
$feedURL = "http://########.tumblr.com/api/read/?num=$numPosts";
$xml = simplexml_load_file($feedURL);
// etc. etc.

#2

Read API docs. http://www.tumblr.com/docs/en/api#api_read

阅读API文档。 http://www.tumblr.com/docs/en/api#api_read

If you give ?num=5 you'll get 5 results.

如果你给?num = 5你会得到5个结果。

On the other hand you can use the following:

另一方面,您可以使用以下内容:

$posts = $xml->posts->post;
$posts = array_slice($posts, 0, 5);

#1

$numPosts = 5;
$feedURL = "http://########.tumblr.com/api/read/?num=$numPosts";
$xml = simplexml_load_file($feedURL);
// etc. etc.

#2