python 正则表达式 re findall 方法能够以列表的形式返回能匹配的子串。
(pattern, string[, flags]):
搜索string,以列表形式返回全部能匹配的子串。先看个简单的代码:
import re
p = (r'\d+')
print ('one1two2three3four4')
### output ###
# ['1', '2', '3', '4']
稍微复杂点比如:
info = '<a href="">baidu</a>' 我们的需求是通过正则表达式提取网址和锚文本,那可以用到
findall()
import re
relink = '<a href="(.*)">(.*)</a>'
info = '<a href="">baidu</a>'
cinfo = (relink,info)
print cinfo
relink = '<a href="(.*)">(.*)</a>'
info = '<a href="">baidu</a>'
cinfo = (relink,info)
print cinfo
输出的结果:[('', 'baidu')] 返回的是一个列表,列表里面是匹配的结果形成的元组形式
例子function:
def get_yizhe_info(url): # url weiyigecanshu
#url='/subject/6082808/?from=tag_all' # For Test
req = (url, headers=hds2[(0,len(hds2))])
html = (req).read()
html = ('\n', '')
#print html
try:
reg_temp='<span class="pl"> 译者</span>: *?(.*?)<br/>'
temp=(reg_temp,html)
print temp
if temp:
reg_author = '<a class="" href=".*?">(.*?)</a>'
name = (reg_author, temp[0])
print name
str=''
for na in name:
str=na+'/'+str
str = (str,str[:-1])
except:
str = '暂无'
return str